Solving the Quintic Equation z^5 + 32 = 0 - Complex Analysis

Solving the Quintic Equation z^5 + 32 = 0 - Complex Analysis

[trigi]

This is a great video. I looked all over the internet for a question like this, and this was the only video that helped! Thanks

[pranavranganath]

THANK YOU! You kept it so simple and straightforward.

[felipebrito]

What if it was z^5-32=0? What would z^5=32 look like in polar form and what would our angle be?

[anakhash]

OMG I don't have enough words to thank you, but you can imagine that I have been trying to understand it for two hours and then I found your video. Thanks again -_*

[theperplexchild]

3mins in and you have helped solve my question. thank you!

[pratiksapkota]

thank you! finally someone with common sense!!

[ThePowerGeek]

helped a lot with understanding de moivre's theorem, thanks!

[arxidaros]

can u please explain why we add +2kπ at 0:56 ?? Which funcion you mean is periodic?

[pratiksapkota]

why not take -1, 0, 1, 2 and 3 as values of K?

[nayansaha]

plot the variation of p1(x )and P2( x )as a function of x
please do this

[mohzoh]

I want to find the quintic root of number 33 by 4 different ways by steps

[NicolasMiari]

Just long-divide by the obvious factor (x + 2) and solve the quartic!

[anjaneyasharma]

Guessing turns out correct
Z^5 2 ^ -5 = --32

[Qusbaz-zgnv]

DO NOT LIE TO PEOPLE. The answer is z = -2.
(-2)^5 + 32 = 0
-32 + 32 = 0

[ruthenianthruth]

Such a bs video. I lost myself from i already. What is i? Why is it there?