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GED Math Test 2014 - Solve by Substitution Tutorial
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A math tutorial on how to solve for variables using the substitution method.
We've got two equations:
y = 8 + 4 * x
2 * y - 20 * x = 4
We've already got the first equation in the form y equals so we can plug the first equation into the y value of the second one.
2 * (8 + 4 * x) - 20 * x = 4
16 + 8 * x - 20 * x = 4
16 - 12 * x = 4
-12 * x = -12
x = 1
Now we can use x = 1 to solve for y by plugging x = 1 into either the first or second equation.
y = 8 + 4 * x
y = 8 + 4 * 1
y = 12
Solving by substitution has given us the values x = 1 and y = 12. Since the equations given were both equations of a line the point (1, 12) would be where the lines intersect.
A math tutorial on how to solve for variables using the substitution method.
We've got two equations:
y = 8 + 4 * x
2 * y - 20 * x = 4
We've already got the first equation in the form y equals so we can plug the first equation into the y value of the second one.
2 * (8 + 4 * x) - 20 * x = 4
16 + 8 * x - 20 * x = 4
16 - 12 * x = 4
-12 * x = -12
x = 1
Now we can use x = 1 to solve for y by plugging x = 1 into either the first or second equation.
y = 8 + 4 * x
y = 8 + 4 * 1
y = 12
Solving by substitution has given us the values x = 1 and y = 12. Since the equations given were both equations of a line the point (1, 12) would be where the lines intersect.
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