Solution Of The Hardest Easy Geometry Problem In Mathematics

In the figure, we have to find the value of x? This problem is known as Langley's Adventitious Angles. It is also known as the hardest easy geometry problem because it can be solved by elementary mathematics but very hard to find out.

[rcnayak_]

We can still find an easier way to solve this problem. Now invert this figure to the other side of BA (Line BA fixed). Let the new triangle be BC'A. As it is a reflective triangle of ABC, line BE will be seen as BE' while it makes an angle of 60° with BC' and 20° with BA. And CE' will be a straight line. Now in the triangle CBE', angle CBE = 60+20+20 = 100°, BCE' = 50°, therefore angle BE'C = BE'F = 180 - 50 - 100 = 30°. Now triangle BFE and triangle BFE' are equal (since BE=BE', BF is common side and their included angles are 20° each). Therefore angle BEF = angle BE'F = 30°. Proved

[endemikmatematik]

Good job. Which program are you using?

[Ravikumar]

Because we can see anything in mathematics we have to prove every thing here 3:55

[mukarramaliofficial]

Sir ye btaye Hum construct kar hi kiyon rahe h
Matlab first construct karne ke liye koi soche GA hi kiyon

[thTime-giqt]

I solved in in 3 days "just 3 days..😅" but I swer I didn't see the solution, Now I have it's easiest solution from which it can be solved in just 2 mins. ( If you didn't believe me reply me will give you it's solution, you will not find that easiest solution any where)...{ I am an Indian 9th standard student}.

[engineer_one_life]

40, 40 wla isosceles triangle ki equals side galat h tumhari

[rahulshukla]

Jabardasti lines ko barabar dikha rhe hain dikha rhe hain
Aise thodi hota hai 😂😂😂😂

[Desmo_Jupiter]

Thankyou sir is question par pichle 1 week se laga hua tha

[avoysardar]

AP ko kaise pata hua bfg icoselas hain

[Mathematician]

It was easy. I think it is the easiest easy geometry problem

[FukreyBoiz]

This is very easy question when i see this question , I solved it in my mind.