Prove that the function f(x) = 1/x^2 is uniformly continous on [a, infinity)

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In this video I will prove that the function f(x) = 1/x^2 is uniformly continous on [a, infinity) where a is a positive number. I hope this video helps someone who is learning how to write proofs.

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You did the best job ever. Be proud and THANK YOU, you did help someone in the world!

KristineSteele-fsyc

Great vid! When I did this exercise I assumed wlog y>=x to estimate further like you did.

HansPeter-cwqv

Shouldn’t delta be only dependent on epsilon in case of uniformly continuous functions?

kushagrasingh

What is the software you use to write and also the device ?
Please let me know

hussainfawzer

Today we took the derivation and I'm excited and nervous about it
can you give me resources to study it ?

Love_hardwork

At the timestamp 5:34, why do we take x to be <= a? I thought x could be anything greater than 0 just like a. Your videos are very helpful

ousmanfitness

I'm stuck, you've proven that |x-y|<𝝳 and |f(x)-f(y)|<ε both hold true but how did you prove that |x-y|<𝝳 IMPLY |f(x)-f(y)|<ε? (since correlation≠causation)

HXED_OwO

Prove that the function f(x) = 1/x^2 is uniformly continous on [a, infinity)

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