Prove the function f:Z x Z → Z given by f(m,n) = 2m - n is Onto(Surjective)

preview_player
Показать описание
Prove the function f:Z x Z → Z given by f(m,n) = 2m - n is Onto(Surjective)
Рекомендации по теме
Комментарии
Автор

why does the pairing (0, -y) work to prove the whole function is onto? what if m is not equal to 0? How does one pairing prove for all pairings?

SchmidtKaiser
Автор

I mean, I can understand that it works, but I don't understand when it wouldn't work.

Nandinandito
Автор

This made absolutely zero sense to me.

FinnishArmy
Автор

DUDE AFTER USING SLADER AND WATCHING THIS VIDEO I FANNYLLYLLY UNDERSTOOD IT

NotJoSa
Автор

Someday pizza delivery will be surjective; it will just appear in my stomach. Until then, I'll have to keep looking for it in the shrubs.

eswyatt
Автор

You are life saver. Thank you for all you do!!

albertlewis
Автор

thank you do much "tears" ❤️

yosufgaper
Автор

How can we check that if this function is one one or not?

Nandita
Автор

Can u tell me how to check whether f(m, n) = |m| - |n| is onto or not?

goplay
Автор

i still coonfuse if (m, n) the codomain is Z x Z and domain which is y is Z if i take 2 then m can be 0 but how n become -2 but there is no Z x Z = -2
or maybe 2

phinkurniawan
Автор

you are using a counterexample to proof which is not correct

jaamalarane