Calculus 3: Divergence and Curl (2 of 26) What is the Gradient?

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In this video I will explain what is the gradient, del operator f(scalar).

Next video in the series can be seen at:
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This has got to be the best video on an introduction to vector calculus out there, thank you so much!

Cadmin
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until I start to apply calculus in my post-grad study, I realize that I really need some simple but detailed instructions and illustrations. here I find what I need!!

weixiao
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As usual, van Beizen to the rescue!
Every exam period brings a new wave of desperate students to complement the good teachers on the net.
Thanks again :)

taladiv
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@6:07, it is important to mention when Z = X^2 + Y^2 = 1, X = .707 and Y =.707, or square root 2 over 2. Then when you plug in for X and Y, you get root 2 i + root 2 j, which the magnitude (slope at that point) is 2.

fcp
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I think The point between should be (1/sqrt2, 1/sqrt2)

RiaziMohandesi
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Thanks, this teacher tell us the concepts well in a intuitive way 😊, it helped me a lot

zzzyout
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@ 6:07 the point in between should be (√2/2, √2/2), and hence the slope magnitude would be 2

ASIR
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Between (0, 1) and (1, 0) on a circular path is (sqrt(2)/2, sqrt(2)/2) not (sqrt(2), sqrt(2))

terjeoseberg
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I would really like to Thank you a lot for taking such a pain to provide such a beautiful & in depth explanation...

sarangdharkumar
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At time 04:32, i think it is better to say :In the direction of The Maximum increase in function, not Maximum increase in slope, or better to say :In the direction of maximum slope.

RiaziMohandesi
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First of all, thank you for a great video series. However, I am lost for the intro video for gradient.
When writing f=f(x, y, z), f is a function of (x, y, z) R^3->R, where x, y, z are independent "input" variables and f(x, y, z) is a dependent "output" variable, for example velocity field f at position (x, y, z), which is not x, y or z. However, in the example f = x^2 + y^2, the meaning of f seems changed to be z or f(x, y)? Considering a level curve of f(x, y, z)=C, it will be a cylinder not paraboloid. Did I miss anything?

yangqian
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how the point between the (1, 0) and (0, 1) on the circular line comes equal to (√2, √2)?
just on the basis of my imagination i think it should be (1/√2, 1/√2).

And this value of x and y can also give magnitude of vector sum equal to 2
Please correct me if i am wrong
And thanks for the great explaination

GursimranSingh
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This was very helpful for me. Thank you very much for your effort.

manueljenkin
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But the function of x, y and z will lead to a 4th dimension and I don't know how to visualise the function in 4th dimension.

spurti
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I have a doubt. Sir chose (√2, √2) and said magnitude is 2(slope).

Firstly, how can (√2, √2) have the same z value as (1, 0) and (0, 1)?

If z is not the same, slope is neither the same right?

And how did you calculate the magnitude? Is it the √((2x^2)+(2y^2)) ?

Then the magnitude of the √2, √2 case will be 4 right?

I'm confused. Thanks in advance.

mohammadsabithali
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I have a question that's been bugging me for a while now. what would be the gradient of f where f(x, y, z)= 1/p. It doesn't give anything about what P represent but since f is a function of three variables, I am guessing p is also a function of the same three variables. So would you use chain rule in problems like this, to find the gradient?

Bearfair
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The points you have labeled (1, 0) and (0, 1) should be labeled (1, 0, 1) and (0, 1, 1), shouldn't they?

dggrossman
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Sir

Michel Van Biezen. How is the ' magnitude of the gradient' defined? This has always confused me. Is it the magnitude of the sum of the magnitudes of the two partial derivatives in the x and y direction, if say z=f[x.y] I would be most grateful if you would care to clarify this for me . Thanks.

barryhughes
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Thank you sooo much !! by the way, isn't it the point (sqrt(2), sqrt(2)) not on 3-dimentional figure which includes (0, 1) and (1, 0).
Isn't it we cannot calculate slope of that point because there is no figure

YuriKim-bbwx
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How is magnitude of 2sqrt (2) i` + 2sqrt (2) j' equal to 2??? It is 4 right?? plz explain the part at 6:16

SidharthShambu