Solve (a^2-4a-12)/(a^2-10a+25)=6/(a-5)+(a-3)/(a-5)

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In this math video lesson on Solving Rational Equations I solve the equation (a^2-4a-12)/(a^2-10a+25)=6/(a-5)+(a-3)/(a-5). This video discusses how to solve a rational equation (an equation with fractions) for a variable and check for extraneous solutions. #rationalequations #fractionequations #extraneoussolutions #algebra1

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  1. Minute Math
  2. (a^2-4a-12)/(a^2-10a 25)=6/(a-5) (a-3)/(a-5)
  3. help with (a^2-4a-12)/(a^2-10a 25)=6/(a-5) (a-3)/(a-5)
  4. how to solve (a^2-4a-12)/(a^2-10a 25)=6/(a-5) (a-3)/(a-5)
  5. help solving (a^2-4a-12)/(a^2-10a 25)=6/(a-5) (a-3)/(a-5)
  6. simplify (a^2-4a-12)/(a^2-10a 25)=6/(a-5) (a-3)/(a-5)
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Комментарии
Автор

Oh no i was being stupid becausd a-5/a-5 is 1 so you don't rode it

IsmaelDiall
Автор

I think you made an error in the beginning because you can't multiply something on the right side if you don't multiply it on the left with the same number

IsmaelDiall