Lagrange Multipliers Maximum of f(x, y, z) = xyz subject to x + y + z - 3 = 0

Lagrange Multipliers Maximum of f(x, y, z) = xyz subject to x + y + z - 3 = 0

[syaw]

Great video. I think there's a mistake at the end of the video since f(1, 1, 1)=1.

[jinlou]

Since we only get one critical point, how do we know whether it's a max or min?

[atocousin]

Thank you Math Sorcerer!! You are one of the best math youtubers ever, thank you for helping out.

[sebiaguirre]

Hello math sorcerer, can you find the extreme value of the function subject to the constraint using Lagrange multipliers?
f(x, y)= xy ; (4x^2)+y^2= 8

[justgay]

but how do we know it's a maximum, lagrange multipliers only tell us that if there is an extremum, such a lambda exists, how do we tell that that is indeed an extremum?

[ArnoldLinda]

What if xyz = x+y+x = 3? I need to find a solution for this.

[sagarbhattacharya]

Sir, in whole youtube only in your videos I find peace ✌️ your vocals are amezing

[nevermind]

3:24 how did you know the variables are positive reply exam tomorrow

[daylatharraulima]

thank you, i was realy struggling before i saw this video

[briendamathhatter]

Time to give you some views, quick late night study sesh