🟡15b - Lagrange's Multipliers: Two Constraints - Find the maximum and minimum | Ex 4 & 5

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In this lesson we are going to use Lagrange's method to find the minimum and maximum of a function subject to two constraints of the form g = k, and h = k

00:00 - Ex 4
10:05 - Ex 5

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1. Applied Electricity

2. Linear Algebra / Math 151

3. Basic Mechanics

4. Calculus with Analysis / Calculus 1 / Math 152

5. Differential Equations / Math 251

6. Electric Circuit Theory / Circuit Design

7. Calculus with Several Variables

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  1. SkanCity Academy
  2. Lagrange's multiplier
  3. Lagrange's multiplier of two side conditions
  4. mminimum and maximum of a function using Lagrange's multiplier method
  5. Lagrange's method for finding min and max values
  6. minimum and maximum values with constraints
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Комментарии
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❤❤Im so thankful to you god bless you sir

Surya_Kiran_K
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This is great, sir. I love it. Keep the good work, from Nigeria.

HenryUbana-gnbj
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Please when you were doing the substitution you had z=-y and you're putting it into equ 5.
So y^2 + z^2 =4 which is equ 5
Now putting z =-y won't give 2y^2 but instead 0 but you wrote 2y^2

edwardwiafeaidoo