Derivative of x^x

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This calculus video tutorial explains how to find the derivative of x^x using logarithmic differentiation, implicit differentiation, and properties of logarithms.

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There is another way to do that without using logarithmic differentiation. You can write y=x^x as e^(xln(x)). Using the product and chain rule, you get

justabunga
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Please edit in a curt bow at the end, and a standing ovation from a live studio audience. Short and succinct :D very helpful

rivercuperus
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Lol you just answered my quiz worth 10pts :D :D

Optmzdlyz
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It looks like the question was more simplified than the answer

nastynateanddaboys
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But I mean why do the ads have to be so directed at the subject

rogerselirogers
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Thank you so much for this basic math solution 🙏 JAY SITA RAM 🙏 JAY HANUMAN 🙏

ruchismitabehera
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It's obvious to see such thumbnail when a chemistry tutor teaches maths 😂😂😂😂😂😂

Integration question
Dy/DX (x^x)

tylerd
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Can't the power rule be applied here

InterstellarCreature
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what if you used the difference quotient?

josephlindenberg
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dont know why did u kept the last 20 secs epmty

gotnoluck
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i still don't get how we got from d/dx ln(y) to 1/y dy/dx (i get 1/y is ln(y)' but the dy/dx is what what i don't get, help???)

seemelater
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how to diffrentiate this using chain rule

raunakkatiyar
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Pehle andar wale ko kaddu maankar bahar wale ka differention kro anf then bahar wale ko kaddu maankar andar wale fnc ka differentiation kro # saleemians

LOWRIDER-lo
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It's obvious to see such thumbnail when a chemistry tutor teaches maths 😂😂😂😂😂😂

Integration question
Dy/DX (x^x)

tylerd