How to use L'Hopital's Rule to Find the Limit of ln(ln(x))/x as x approaches Infinity #shorts

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How to use L'Hopital's Rule to Find the Limit of ln(ln(x))/x as x approaches Infinity #shorts

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Комментарии
Автор

I immediately knew. Because lnx<x for all x>1, we can immediately recognize that ln(lnx) is a smaller infinity. Hence, the limit approaches zero.

jacobstarr
Автор

Well if you studied things about complexity and the big O notation, you probably know that O(ln n) is already way better than O(n), and O(ln ln n) is even better, so this limit is easily 0 by knowing that ln(ln x) is having a speed of increase way slower than x

not_vinkami
Автор

What happened if we have the same problem but x goes to 0 help please

danielcepedavillarraga
Автор

what the faaak, that went a bit to fast mate

hansjacobthordalsloth