Lagrange multipliers: 2 constraints

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This video shows how to apply the method of Lagrange multipliers to a max/min problem. Such ideas are seen in university mathematics.
  1. Dr Chris Tisdell
  2. mathematics
  3. engineering
  4. example
  5. solution
  6. Lagrange
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Комментарии
Автор

Putting 2x-y=0 made your question be very easy. If it was not there, how would we go about it

jmoriarty
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Suppose I have three interdependent functions: A, B and C.
Then, I will write a Lagrangian L1 = A-l1((B-b)-l2(C-c)
Extremizing the Lagrangian will give me the multipliers l1 and l2.
But then, could I write two more Lagrangians
L2=C-l3(A-a)-l4(B-b)
L3=B-l5(C-c)-l6(A-a)
Extremizing the latter two Lagrangians should give me the multipliers l3, l4, l5 and l6, right?

petripaavonpoika
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How can we say that this will find maximum value of f?
If we have to find minimum value of f then what will be the procedure.

anshimasingh
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I get everything else, but cannot see how you got Lambda 2 to equal 4 lambda 1 @6:50.

FB-trkf
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I am from India
people of India interested in math
how people think about India in this matter like math
please any foreigners reply Thank you

ujjawalbarnwal