Horizontal and Vertical Asymptote of Rational Function | General Mathematics

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MathTeacherGon
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hi sir, thankyou po ng sobra sa tutorial n'yo. ang bilis sundan at maintindihan, grabe ang lito ko sa module kung pa'no, kakatamad sundan aa. pero ang sarap niyo po magturo, nakakagana. Godbless, sir. 😩😩❤️❤️❤️

imjen
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f(x)=2/2x+3

V.A.
2x/2=-3/2
x=-3/2

Thus, the vertical asymptote is x=-3/2

H.A.
n=0 m=1
n<m y=0

Thus, the horizontal asymptote is y=0

superidoldexiaorongdoumein
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hi sir, exam namin sa monday and stress na talaga ako kanina dahil wala akong alam sa math topic namin, i'm so lucky na nahanap ko tong channel mo, ambilis ko nagets and medyo nawala yung takot ko for my exam in gen math, nawiwili na ako sa math kanina pa ko nanonood ng mga vids mo na abt sa topic namin hehe, tysm!!

aokifuji
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Big help..galing tlga ni sir mag explain..

windadingal
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3.Given
F(x) = 2/2x+3
V.A
Equate 2x+1=0
2x=-1
Devide both by 2
÷ 2x=-1
2 2
x=-1/2
Our V.A is -1/2
H.A
n=0 m=1
n < m
H.A is y=0

johnservidad
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sir napaka galing niyo mag turo kahit naka mute po naiintindihan ko po thankyou sir

camreston
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may exam narin kami nextweek buti nlg nahanap ko channel mo sir salamt po

jovenerafa
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f(x)=2/2x+3

V.A.
2x+3 = 0
2x/2 =-3/2
x=-3/2

Thus, the vertical asymptote is x=-3/2

H.A.
n=0 m=1
n<m y=0

Thus, the horizontal asymptote is y=0

JoseRaymondDamianSalvador
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Salamat sir na gets ko agad huhu dugo na utak ko kakabasa HAHAHAH hirap po kase sa self study

joshuaalbello
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thank you po sir pina dali nyo buhay ko ^_^
<3 <3

christianpatrickcabral
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mas naiintindihan ko pagturo nyo sir mabagal lang e, sa sir namin ang bilis magturo, thankyouuuu sir gon na nasa hunter x hunter HAHAHAHA jk lgpo, ty poo

jovenerafa
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V.A.
x=-3/2
H.A.
no asymptote (numerator do not have a degree)

GooEnoki-dguh
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my answer is VA ( 2, -3)
Y=0

LET ME HERE YOUR COMMENT

marycilortegavlogs.
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what if hindi po ma factor ang trinomial?

lambswkswkswk
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hi sir pano po mag report ng vertical and horizontal asymptotes

SaripWari-xqlm
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3.) f(x) = 2/ 2x+3

V.A.

2x+3=0 Transpose 3
2x=(-3) Divide both sides by 2
2x/2 = (-3)/ 2 Cancel
x= -3/2

Therefore, the vertical asymptote is x= -3/2.

H.A.

f(x)=2/2x+3
n=0, m=1
n<m, y=0

Therefore, the horizontal asymptote is y=0.

Tama po ba, sir? Or mali?

johnella
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Wala po ba ser para sa obliuqe/slant asymptotes?

artbrylie
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My Answer
V.A #3.x=-2, -3
H.A#3.y=3
Ok batung answer ko sir?

ronaldelcarte
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Sir pano po Kung Hindi perfect square of binomial?

jaspherquinto