Probability Problem Involving ' At Least ' and ' Complements '

[timengstrom]

Still not seeing why you use permutation not combination

[dungKHTNcs]

A wonderful video! Wish you more success in the future :)

[leovolont]

The question is the P of at least 2 boys choosing the same Watch, then Patrick the Genius says that it is Choice With Out Replacement, which would make it Impossible for two boys to choose the Same Watch. Is this supposed to be Joke to see how many people are stupid enough to go along with it.

Also, the question was "at least 2" but his Negation was the Case of Zero boys choosing the same watch. Well, what about the case of just 1 boy chosing the watch. The Negation would be the Sum of Zero Boys and 1 Boy.

Now, what exactly did he do? 1 minus the Total Number of ways a Set of 5 can be Ordered from a Set of 12 OVER the Total number of ways a Set of 12 could be ordered in sets of 1. Now, how the heck is THAT supposed to solve our problem of about at least 2 boys out of 5 picking the same watch out of 12. If there is a connection there, well, Genius did not explain it very well.

the only thing he was right about was that he is confused by Probability Problems.

[patrickjmt]

well, i have been to holland, and i have no tattoos :)

[bbencosme]

Patrick I wish you can take my Stat course is killing This turtorial is clearing things up a bit.  I am just plain with math stuff.

[Dynamikwun]

i still not getting how the order matters, if we have the sample space as 12^5 then this means that each of the 5 boys has the 12 styles to chose from. If the first boy picks a rolex it does not affect the second boy, he still has 12 to choose well imo, could you clarify this for me please

[pioneeringworks]

This problem is similar to birthday problem in Khan Academy.
The order matter (in my interpretation) because we're calculating (look above) in the numerator the every possible way of not having the same watch. And note that we're not calculating every possible way of "picking the same watch" DIRECTLY. We're solving this problem literaly by elimination (1 minus not having the same). So the question "does order matter" does't apply in our situation. It does make sense when you see that in the numerator it's calculating every possible way of unrepeatable permutations while in the denominator every possible way of repeatable (repetetive) permutation. Dont take this as a fact it's just my opinion.

[unknow]

does the "at least # of boy chose the same watch" even matter here? would the result be different if 3 or 4 or 5 boy chose the same watch... Since it's going to be same formula anyway?

[patrickjmt]

i have no idea what that joke is even supposed to mean.

[johnoptions]

In the statement it is not clear whether the picked watched is replaced before the next student picks. Why is this information not provided and assumed?

[rajaniswar]

its not clear whether each watch is different style ..if each is a different one, how can denominator be same for each watch selection? very confusing

[snoopdogg]

I was looking to solve a problem like this: Odds of picking a certain card or rolling a certain number on a die, both being mutually exclusive. Both events are at the same time but do not influence each other in anyway.Anyone know how to go about doing this?

[kimp.dr.n]

I have decided probability is for people who like to overthink simple things.

[romulus]

I don't need to take any more math classes for my B.S, but I still watch patrick's videos cause he's so good at explaining math!

[MrPagads]

That was a nice explanation..it did refresh my probability knowledge!! thanx a lot. waiting to have more.

[HieuNguyen-rcum]

Thank you! This video is very helpful!

[addalilirishtourgame]

i think what he is saying, is that the chances of you going to holland is less likely then you getting a tatoo. of a calculator. (lame and weird i know)

[HotPepperLala]

Oh my god. I am taking college probability this summer and our prof just talks to herself. More probability pleasseee

[voidsonvoid]

Please do a video on discrete random variables, continuous random variables, and normal random variables.

[musicminded]

Why is the negation, None of them choose the same watch?