Evaluating a Limit at Infinity by Using the Squeeze Theorem

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  1. Daniel Kopsas
  2. limit
  3. infinity
  4. squeeze
  5. theorem
  6. exponential
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Thanks for the video. I have a question:
Why not say like this:
lim e^x * sin(x) (x -> -inf) = [ lim e^x (x -> -inf) ] * [ lim sin(x) (x -> -inf) ] (by using limit rules)
then we have -> lim e^x (x -> -inf) , so:
lim e^x * sin(x) (x -> -inf) = [ lim e^x (x -> -inf) ] * [ lim sin(x) (x -> -inf) ] = 0 * [ lim sin(x) (x -> -inf) ] = 0

Can this be correct? I'm started to feel it's not :)
Because lim e^x (x -> -inf) approaches 0, not becomes exactly 0 (because it's limit)
so we can assume that it's some small number like and then my way of finding the limit is wrong.

Which one is correct?
thanks overall.

neotodsoltani