Joint Probability Distribution # 2 | Conditional Probability Distribution, Independence

I hope you found this video useful, please subscribe for daily videos!
WBM

Foundations: Mathematical logic Set theory

Algebra: Number theory Group theory Lie groups Commutative rings Associative ring theory Nonassociative ring theory Field theory General algebraic systems Algebraic geometry Linear algebra Category theory K-theory Combinatorics and Discrete Mathematics Ordered sets

Geometry Geometry Convex and discrete geometry Differential geometry General topology Algebraic topology Manifolds

Analysis Calculus and Real Analysis: Real functions Measure theory and integration Special functions Finite differences and functional equations Sequences and series Complex analysis Complex variables Potential theory Multiple complex variables Differential and integral equations Ordinary differential equations Partial differential equations Dynamical systems Integral equations Calculus of variations and optimization Global analysis, analysis on manifolds Functional analysis Functional analysis Fourier analysis Abstract harmonic analysis Integral transforms Operator theory Numerical analysis and optimization Numerical analysis Approximations and expansions Operations research

Probability and statistics Probability theory Statistics

Computer Science Computer science Information and communication

Applied mathematics Mechanics of particles and systems Mechanics of solids Fluid mechanics Optics, electromagnetic theory Classical thermodynamics, heat transfer Quantum Theory Statistical mechanics, structure of matter Relativity and gravitational theory Astronomy and astrophysics Geophysics applications Systems theory Other sciences

Category

[thiesus]

I dont understand how you got 2/8, 5/8 ect... you said it is likely to happen 3 times...omitting this..that.. can you please explain? thanks

[samyakshah]

I think there may be an error with the problem. When I add all the probabilities on the table, they sum to 25/24. Aren't they supposed to sum to one?

[catherinemusau]

I didn't undestand how u are getting those values, 2/8, 5/8, 1/8, please do another one and explain better

[mamadoujallow]

thanks for this video its really helpful. however; i dont understand the part where you divided the denominator of 6/24 by 3 what is the reason for that and if y was = 2 what would you do?

[sanjaykrish]

There is a slight mistake in the explanation. We get the conditional distribution of P(X=x|Y=1) by normalizing the x values for Y=1 i.e., divide each entry of x for Y=1 by the column sum which in this case is (1/3). So (2/24)/(1/3) = 2/24 etc etc

[hype_henry_it]

why the title of the video is Joint Probability while the video is about conditional probability? Thanks

[ciarawalsh]

Hi thanks for the video, what would you do if you were asked for the P(X+Y <= 1)? Thanks

[ReinierRuneScape]

It would be more simplistic to do: P(X = x) / g (y) = P (X = x | y = 1), or in number language: (2/24)/(8/24) = 1/4

[lawrenceedemzikpi]

where is the previous example? i cant find it

[nokya]

will anyone could answer my assignment about multivariate probability but i cant attach here the assignment

[linhtruong]

the sound is not good I am quite disappointed