Conditional Probability given Joint PDF

After making this video, a lot of students were asking that I post one to find something like:
Pr(X greater than 1 GIVEN Y greater than 1)

[Evil_Narwhal]

I really hate how the professors go over the simplest examples but then the homework has in depth problems like these. Thank you so much.

[leahwilliams]

Seriously. Thank you. My professor didn't explain this very well, but it was totally on the homework. You did a great job explaining.

[kushalmohnot]

I've fallen in love; what an incredibly clear thought process!

[wanhope]

explained in simple terms. helped me more than hours of listening in my probability class. Thank you !

[StatsWithJesse]

Great video - thank you. I studied applied mathematics a few years back, and I quickly forgot some important things. I needed this video- it was clear and concise.

[movocode]

Thank you sooo much - you helped me in very last moment of my exam prep - literally seeing this 1 hr before my exam starts. Love from India.

[mirandaatangdithebe]

Could'nt have asked for a clearer video, thank you sm.

[baqerghezi]

Great video thank you.
also we can see the answer is 1 from the support (1<x<2) it is always greater than 1

[kkikkodan]

thanks so much. my sir did this in short but didn't give reasons for the way things were. so this was very helpful. love from India.

[cleo]

Thank you for saving my life. Seriously.

[pppeterrrr]

thanks, its very straightforward and clear

[tvvt]

8:14 hi, if instead of a specific value, if it were given Y<1/2 then would we simply integrate the conditional function from the lower limit to 1/2 OR do we substitute Y in the conditional function with any value within its range that is less than 1/2

[topstuffspotter]

Great Explanation! and your voice is really sweet.

[ihsanerben]

YA SEN NE BÜYÜK Bİ ADAMSIN BE KARDŞEİM

[rye-bread]

Jesus. I regret college. I could have been a fantastic electrician and probably make almost as much.

[rheabali]

how would we evaluate the conditional probability when y is "less than/equal to" say 1 instead of equalling 1?

[sheetalkumar]

why is the first part of the integral -> -inf to y for f(x, y)dx = 0 ? Shouldn't it be integrated in that range ?

[mohitgupta]

thank u so much, i wish my professor learn how to tech like you

[YokiWong]

Thank you so much for the great video!

[malcolmlamya]

Thank you, it helps a lot. God bless.