Taylor's Remainder Theorem - Finding the Remainder, Ex 3

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  1. Patrick J
  2. taylor
  3. taylor's
  4. remainder
  5. theorem
  6. series
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this helped me so much! we have a test on taylor and maclaurin/power series tomorrow. i'm definitely showing this to everyone in my class...

shilpakancharla
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When he use 0.3 as a valu of z, the aim of the problem is not to approximate e^0.3... It is to determine the error using the polynomial to estimate e^0.3... it is more like using technologie to calculate the error when we use the Maclaurin polynomial of deg 2 of e^x...

fred
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Why would you plug in 0.3 as a value of z? The aim of this problem is to approximate e^0.3. And if you use e^0.3 to evaluate the derivative, it would defeat the purpose of approximating the original function. It's like using the answer to solve the answer, which doesn't quite make sense... Aside from that, your videos are very helpful, and explains the material clearly. :)

anumita
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but it wouldn't be negative 4 once you plug it into the equation right? because you're taking the absolute value.

lonewolfnh
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Thanks so much! One quick question about your remark. If the function for example was 1^x then choosing negative 4 gives a number with smaller magnitude than if you chose positive 1. In that case would it be better to chose 1?

XanderManTKD
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Hi, you are using maclaurins expansion instaed of taylors.

ngugimuiru
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