Finding the Vertex Of Parabola

[MacClintock]

Another approach is to factor and rewrite it as y = 3(x+2)^2 - 7

I like how the answer can be immediately seen in this form. The vertex occurs at x+2=0 and y=-7

[Quissayilen]

Learned more from you than my college professor❤ thanks for making it easy to understand I really appreciate this🌸

[zahariastoianovici]

Excellent, so easy to learn, thank you! Wish I had math presented this way 45 years ago when in school! Learning again and enjoying this logic now is such a refreshing exercise for depression

[MatthewVivanco]

Instead of plugging in you can use synthetic division, whatever the remainder is that’s ur min/max.

[avisibleparadox]

or take the first derivative of the given parabola and set it equal to zero and evaluate (this works because of the minima of the parabola that is the vertex)

[chiragtulsani]

Since this is a parabola that opens upwards or downwards, you can also take the first derivative and the slope at the point where the vertex is will be zero.
y= 3x²+12+5
Differentiate w.r.t x
dy/dx = 6x+12 = 0 (the derivative is the slope of a function)
6x + 12 = 0
x= -2
Put the value of x back in the original equation
y= 3(-2)² + 12(-2) + 5
y= -7
Hence the vertex is (-2, -7)

[marianondrejkovic]

Derivation Still seems to be much easier to Remember

[ArthurBri]

In the next video, show a figure that represents the result, this helps a lot with understanding.

[yan]

That surely is the easiest way to get the solution. Great work !

[leviwright]

Another way to find the y of a vertex is using the equation c - (b^2 /4a).

[MrHBox]

I think it’s better to either differentiate or factorise. These methods are much easier to remember than a formula and apply to other situations.

[anestismoutafidis]

y=ax^2+bx+c <=> Xs=-b/2a <=>
y=3x^2+12x+5 <=>Xs= -12/(2•3)
Xs=-2 (put in the first equation)<=>
y=3•(-2)^2+12•(-2)+5<=>y=-7
The vertex of the parabola is
v=(-2/-7)

[followfy]

Someone please find this man.





I want to thank him

[user_drs]

Those who are watching mrhtutoring shorts from India 👇

[tokisakikurumi]

good way to find the vertex, untill you see the question required to use completing the square to find the vertex

[xfljzot]

Professor, I figured it out differently,
x = -b / 2ac, sos, x= -12/ (2*3*5), x = -12/ 30, x incinclitude -2/ 5. incentitude, uclide, -.4.
y=-b(a) + c where c is the inetitude of y sound value.
y= -12 (3) + 5; y = -36 + 7, y= -37 + 7 + 1, -30 + 1, -29.
x= -.4, y = -29, the x and y value for the vertex of eq.

[tentenchu]

You switched from two different markers, a white board, and being silent, to using a chalkboard and talking!

[nilsalmgren]

Ti 84 with a min or max function is even easier.

[dougr.]

This is rote memorization. Something we were not supposed to do, years ago. This only works because a) calculus says dy/dx = 0 gives a minimum or maximum value for a parabola WHEN and ONLY WHEN the parabola is not oriented on a skewed axis and there is an axis of symmetry parallel to the y axis. How to obtain the vertex of a SKEWED axis of symmetry parabola?

[Potencyfunction]

I think he mean inflection ( not vertex)