Learn how to find the vertex of a parabola

👉 Learn about the parts of a parabola. A parabola is the shape of the graph of a quadratic equation. A regular palabola is the parabola that is facing either up or down while an irregular parabola faces left or right. A quadratic equation is an equation whose highest exponent in the variable(s) is 2.

The parts of a parabola include: the axis of symmetry (the line passing through the vertex of the parabola to which the parabola is symmetric about), the vertex (the point at which the parabola turns), the domain (the set of possible x-values of the parabola, usually all real numbers for regular parabolas), the range (the possible y-values of the parabola which is usually the region above the vertex inclusive or below the vertex inclusive for regular parabolas), the x-intercepts (the points where the parabola cuts the x-axis) and the y-intercepts (the point(s) where the parabola cuts the y axis.

Organized Videos:
✅Graph a Quadratic in Standard Form
✅Graph a Quadratic in Standard Form | Learn About
✅Graph a Quadratic in Standard Form | Essentials
✅Find the Parts of a Parabola
✅Graph a Quadratic in Standard Form | ax^2+bx+c
✅Graph a Quadratic in Standard Form | x^2+bx+c
✅Graph a Quadratic in Standard Form | ax^2+bx
✅Graph a Quadratic in Standard Form | ax^2+c
✅Graph a Quadratic in Standard Form | ax^2

Connect with me:

#GraphQuadratics #QuadraticFunctions #BrianMclogan

[soul_so]

This made me feel dumber than I thought I was

[NickedYT]

For anyone confused, here is another way


To start off, if it's in vertex form, you can just watch the end of the video, but if it's in standard form, then get the "a" and "b" from "ax^2+bx+c=y" and plug it inside the equation "-b/2a." Then that will get you the "x" point of the vertex, then all you have to do is plug the "x" inside the equation to find the "y". Then you're all set. if you are going to graph it, keep reading, this method is easy. Let's say the vertex is (-1, 7), then once you plot it on the graph, find another "x" point, one that is larger than the "x" point of the vertex, and one that is smaller. Then you do the same thing and plug the "x" points into the formula to get the "y". Once that is done, plug them in and connect the dots!

[kowenaucoin]

This guy taught me more in 6 minutes during the test than my teacher did In 2 days

[mrklyfe]

Am I the only person who said wait when he erased the board

[muiiriss_]

i have gotten 0% on all of my math stuff ever since we started quadratic functions

[gabel]

THANK YOU, SIR. I've been sitting in my math class confused and your video cleaned things up completely. I wish that you were my teacher 😅

[clirimmurati]

Teacher you're complicating things thats bad for a student for me dont factor just do it simple with derivative or -b/2a thing

[Karinaa___]

im like so close to not even trying for my eoc cause covid screwed everything up and i literally cheated through school for the past year and a half. Theres no way i could ever learn through online school so R.I.P. dream job

[raynewelser]

This is midterm prep at its finest. Thanks!!

[johnwisotsky]

thanks for the help, feel like I️ have 2 professors now 🤘🏽

[sirprodinghamtherdofpigeo]

Thank for this, we had a lot of snow and didn’t have enough time to cover up all of vertex form
Your a lifesaver

[Skyverb]

If you were confused at first like me and got a different Y; you're doing it wrong:

-x^2 Is really: -1(1)^2 [The 1 in parenthesis being the X value we found in this problem he presented]
Remember that a variable without anything in front of it is multiplied by 1.
So -x^2 is not positive 1 (the square of two negatives). It's -1 multiplied by 1^2, which equals negative 1. The solve the rest by plugging in the X value you found for the rest of the problem.

I was dumb and didn't account for the "multiplied by 1" situation.

[fabianvasquez]

Thank you so much i have finals tomorrow and, help me so much today.

[rebeccajazwierski]

Brian, I want to thank you for your videos. If it weren't for you, I wouldn't have succeeded in my college algebra class this semester.

[professorshifu]

That was an awesome lecture! Thank you.

[AntonioVivaldi]

Who else is being distracted from his class by reading the comments?

[soulstitches]

I got a test on this in a few hours, wish me luck!

[deli]

Does it have to be a perfect square trinomial to find the vertex or is this a special case? The problem I'm dealing with doesn't seem to be

[meghanakshirsagar]

(b/2) ^2 !!!! It helps a lot. Thanks Sir!!

[asharibimran]

PLz if u could explain when to/not change the signs of (h, k)I'm about confused while doing it