Quantum Chemistry 7.7 - Hydrogen Atom Radius

preview_player
Показать описание
Short lecture on measures for the radius of the hydrogen atom.

The Bohr radius is 0.529 Angstroms, or a_o. The expectation value of the radius of the 1s hydrogen orbital is 1.5 a_0. The most probable value of the radius is 1.0 a_o. Alternatively, we can compute a probability radius, where a certain percent of the electron density falls inside the given radius.

--- About TMP Chem ---

All TMP Chem content is free for everyone, everywhere, and created independently by Trent Parker.

--- Video Links ---

--- Social Links ---

--- Equipment ---

Microphone: Blue Yeti USB Microphone

Drawing Tablet: Wacom Intuos Pen and Touch Small

Drawing Program: Autodesk Sketchbook Express

Screen Capture: Corel Visual Studio Pro X8
Рекомендации по теме
Комментарии
Автор

nit-picky comment:

the "dr" was accidentally left off of the <r>1s integral.

EdwardCullensMayo
Автор

I've been thinking... yet i'm not sure why one of the volume element in spherical polar coordinates is rsinθdΦ instead of just rdΦ.
it seems sinθ is there so rsinθdΦ is on the xy plane. but why?

nkyu
Автор

I've been watching these and following along in McQuarrie and Simon and I noticed that in the text they multiplied R(r)*R(r) by the full area of a sphere, 4*pi*r^2, yet you only multiplied by the r^2 term. I was wondering about the reasoning behind this. Is it because probabilities are proportional so the 4*pi doesn't matter, or is there some other reason I'm missing?

thomaslassitter
Автор

Hi Trent, is the Pnl(r) function supposed to be followed be volume element dr such that the probability of finding the electron between r and r+dr is (4r^2)/(a0^3)exp(-2r/a0)dr ?

RishabChawla
Автор

The second term in the volume component. Is that rd(theta) or rd(phi)?

mikusxlr