Conditional Probability For X given Y is less than 1 Provided we have the Joint PDF

Find the conditional probability that X is less than 0.5 GIVEN that Y is less than 1.

[FlipDeCoin]

This taught me in the first two minutes what my graduate-level professor was unable to teach over two days. Thanks!

[micahross]

I like your style. You and Mancinelli are the best. Thank you.

[dasellcalipay]

What a big help! You explained it very well. Thank you so much :)

[arslanMCL]

Nice Video. Between which device you are using for writing on screen

[reaganolguin]

could you solve the question by factoring the joint distribution into x(2-y) which shows the two variables are independent. Then by knowing that the marginal density of X is proportional to x you find the the constant "c" which satisfies c * integral (x) from 0 to 1 =1. Then finally you integrate x from 0 to 1/2 and then multiply by to get the answer. I ask because that is what I did.

[sirmexicanelmo]

What if Y=1 and not less than. I am assuming you would still have to find the marginal distribution but I don't think you would then take the integral. What would you do instead? Or would you take the integral?

[jaiicee]

Thank you so so much ! Ugh. Been struggling with this topic 😣

[anjalisahoo]

Let X and Y be independent random variables and both of them
are uniformly distributed in [0, 1]. If the smaller (of the two) is less than 1/4, then what is the
conditional probability that the larger is greater than 3/4? please solve this

[rakeshky]

can u please help me how to do for exponential function with x and y

[watasn]

For more solved question on the Joint Probability Density function click on the link below:

[likeshareandsubscribe]

in case pr(X<1) when we solve this why we take integration from 0 to 1 since X<1 we must take integral from 0 to 0.99 i am right or wrong????
plz guide me.