How to Solve for the Coefficient of Friction

In this video tutorial I explain how to use the friction force equation to solve for the coefficient of friction.

[quacxks]

This is gonna help me much.
Have a physics test tomorrow,
Will update.

Update: 92%!!!
Let's,

[sapaiVFX]

Thx a lot for this. Helped w/ my IB physics lab report

[monikachaudhary]

Hi, Thankyou so much .
Lots of love 💕💕 from INDIA.

[yaduvanshiayush]

It's amazing explanation..!! Love from India dude ❤💗

[kevinkinal]

The 10 sec version Coef of Friction = Force/ wt.
For ex, if 1 lb moves a 2 lb object Coef = .5 (it takes half the wt to move it)

[prttysus]

you saved my life, THANK YOU SO MUCH!

[jinanabrahams]

Thanks so much. My teacher just threw me in the deep end, and this really saved me😊

[danuwu]

Thank you so much, you made it so easy for me!

[jyotsnarishita]

It helped me a lot thanku
I am glad I watched your video
I got 100 /100 💯💯

[andrefelipe]

Thank you ! 😃 you made it look quite easy, I am not even good at math and I understood that 😅.

[VinsanityNailed]

Please please please leave your units in. You don’t explain WHY the coefficient of friction doesn’t have units. It’s because the units divide out. Leaving units out is a really bad habit for students

[twangerrrrrr]

I have my grade 11 physics dynamics test next period in a couple of minutes. I hope I do well. I missed 2 days of school because I moved homes and now I fell behind in friction and gravitation.

[dianelibarnes]

Thank ❤️❤️❤️ I was really having troubles with this one 😭😭

[BattierJam]

Thank you so much for this my teacher is terrible at explaining things

[annrahennaramirez]

thank you this is the video that im looking for two days hahahaha

[jippo]

What if i have to calculate the coefficient of friction in an angle and with the downwards force. For example when i have a box on a sin=15° degree angle slope and the downwards force "gravity" is 200N. I have been trying to solve this for two days and i'm supposed to get the answer Gx = 51, 763N. I just dont get it. The equation goes sin=15°, G=200N, Gx=Fu. Sin= Gx:G, Gx= 200N • sin15°, Gx= 51, 763N. What am i missing?

[NikiweMokoana]

How do you calculate the coefficient if there where two blocks with different masses connected

[gordspins]

yes. this video was very helpful thanks

[samsonphiri]

Since the 7 tones load is pulled along horizontal the normal force= weight of the Load which is equal to 68600N and the acting at the of 30° by the free body diagram the horizontal force = 39606.23N this is the force which must be overcome to accelerate the load of 7000kg.

[gabriellesanthya]

Hi is it possible if you explain superposition theorem 😊