Solve the Logarithmic Equation in TWO simple methods | Math Olympiad Training

preview_player
Показать описание

Today I will teach you tips and tricks to solve the given olympiad math question in a simple and easy way. Learn how to prepare for Math Olympiad fast!

Need help with solving this Exponential Equation? You're in the right place!

I have over 20 years of experience teaching Mathematics at American schools, colleges, and universities. Learn more about me at

Solve the Logarithmic Equation in TWO simple methods | Math Olympiad Training

#SolveTheLogarithmicEquation #OlympiadPreparation #CollegeEntranceExam
#OlympiadMathematicalQuestion #HowToSolveOlympiadQuestion #MathOlympiadQuestion #MathOlympiadQuestions #OlympiadQuestion #Olympiad #AlgebraReview #Algebra #Mathematics #Math #Maths #ChangeOfBaseRule
#MathOlympiadPreparation #LearntipstosolveOlympiadMathQuestionfast #OlympiadMathematicsCompetition #MathOlympics #SolveSystemofEquations
#SolvetheExponentialSystemofEquations #LearnHowToSolveThisQuestionWithoutAnxiety
#blackpenredpen #ExponentialEquation #Exponential #Equation #MathOlympiadTraining #LogarithmicEquation #LogarithmicEquations #Logarithmic #Logarithm #OlympiadMathematics
#SATTestPrep #CompetitiveExams #CompetitiveExam

How to solve Olympiad Mathematical Question
How to prepare for Math Olympiad
How to Solve Olympiad Question
How to Solve international math olympiad questions
international math olympiad questions and solutions
international math olympiad questions and answers
olympiad mathematics competition
math olympics
olympiad exam
olympiad exam sample papers
math olympiad sample questions
math olympiada
British Math Olympiad
blackpenredpen
olympics math
olympics mathematics
olympics math activities
olympics math competition
Math Olympiad Training
How to win the International Math Olympiad | Po-Shen Loh and Lex Fridman
Po-Shen Loh and Lex Fridman
Number Theory
There is a ridiculously easy way to solve this Olympiad qualifier problem
This U.S. Olympiad Coach Has a Unique Approach to Math
The Map of Mathematics
mathcounts
math at work
exponential equation
system of equations
solve system of equations
solve the equation
How to Solve the Exponential System of Equations
How to Solve the Exponential Equations
How to solve Nested Exponents
How to Solve the logarithmic Equations
pre math
Olympiad Mathematics
Competitive Exams
Competitive Exams
imo
Change of base rule

Subscribe Now as the ultimate shots of Math doses are on their way to fill your minds with the knowledge and wisdom once again.
Рекомендации по теме
Комментарии
Автор

Sir thanks a lot for posting this video

yasirhabib
Автор

East to west your second method is the best 👌 👍 😍

Nothingx
Автор

I always try to watch all of your videosIt has increased my power of thinking in math.Allah bless you

allahlover
Автор

Wow gee! Thanks so much for the birthday gift man!!! Love it

SuperYoonHo
Автор

شكرا لك، حلول مبسطة وسهلة يستطيع الطالب فهمها بسهولة دون اي معاناة.

hassanmahdi
Автор

really a great teacher for improving the different concept of maths

janakibhatta
Автор

This problem has many ways to solve
I solved another two ways
Thanks for the lesson Sir

mohamedinsaf
Автор

Very interesting task. And both methods of its solution are perfect. I even don`t know which of the two ones is better..Thank you so much, Mr PreMath! I wish you successful next week and in general all the best in your life!

anatoliy
Автор

I've one more ways to solve this given problem☺️😊
Btw Thankyou sir🙏🏻🙏🏻for all your efforts.

Ajay_Vector
Автор

Second method is simple and straight forward one.

However the first one gives an opportunity to know about new logarithm identity

sandanadurair
Автор

Hi sir, it’s a fun and interesting question. As I tried to solve, I turned out finding another method, below is my method and steps:

Log base2 289= log base2 17^2= 2 log base2 17

By changing the base, we get:
2((log base17 17)/ (log base17 x)) = 2( 1 / log base17 x)

Since log base17 x = 8/9, we plug this result into our step:
2 ( 1 / (8/9)) = 9 /4

DavisMaths
Автор

log x 289 =9/4 or 2.25 ANSWER
17^8/9=x change to exponential form "equation 1"
x^n=289 change 'log x 289=? to exponential form (note n=?)
x^n=17^2
(x^n)^1/n= (17^2)1/n raised both sides by 1/n
x =17^2/n "equation 5"
17^8/9= 17^2/n since equation 1 and equation 5 = the same value, x
8/9= 2/n since both have the same base
8n=18 cross-multiply
n=9/4 or 2.25 answer

devondevon
Автор

this was very well explained, thanks for sharing both methods

math
Автор

how to use white broad like u to do math plz tell me sir....

itspi
Автор

log 17 to the base x is equal to 9/8.

therefore ans

susennath
Автор

If you write the first equation as ln(x)/ln(17)=8/9 and the second as 2*ln(17)/ln(x) it becomes trivial since you get immediately 2*9/8=9/4

Mylorz
Автор

Given logₓ17 = 8/9.
Now logₓ17 =1/log₁₇x
⇒ 2*logₓ17 = logₓ17² = logₓ289 = 2/log₁₇x = 2*9/8
⇒ logₓ289 =9/4

davidbrisbane
Автор

Both methods are good but the second is the easiest one

d.sambasivaraosivarao
Автор

Haha i just solved it in my mind. Lol. It was damn easy.

AdityaKumar-gvdj