Limits using Taylor series[Calculus]

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In this video, I shown how to take limits of (x-sinx)/x^3
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THANK YOU, THIS IS THE FIRST VIDEO I UNDERSTOOD ABOUT TAYLOR SERIES

sydneytshepiso
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Thank you sir . I kept on forgetting this series but now it is helpful.

Pulkit-txih
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thank you so much, I haven’t seen better explanation before

methmatician
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Squeeze theorem could help but you should choose inequalities correctly
I prefer triple angle approach to this limit

holyshit
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I really like how you explained it! But I almost didn't click on the video because of the thumbnail. You should try some picture with you as it would look more legit. Just my take :)

andreimelinte
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Hello sir I been wishing to chat with u thanks for the video

b.hallisonf.thomasEinstein
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Isn't it easier to just use mclaurin here so that you get X-X-1/3!(x^3) / x^3 then you get x^3/6 / x^3 and from here you can multiply both for 1/x^3 and thus get the answer? or am I doing anything wrong?

Я_Яша