Solving A Nice Diophantine System

preview_player
Показать описание
🤩 Hello everyone, I'm very excited to bring you a new channel (aplusbi)
Enjoy...and thank you for your support!!! 🧡🥰🎉🥳🧡
❤️ I still couldn't find my VOICE! 😜😮😁😄❤️

When you purchase something from here, I will make a small percentage of commission that helps me continue making videos for you.
If you are preparing for Math Competitions and Math Olympiads, then this is the page for you!
CHECK IT OUT!!! ❤️ ❤️ ❤️
❤️ ab + cd = 6 and ac + bd = 5

If you need to post a picture of your solution or idea:
#radicals #radicalequations #algebra #calculus #differentialequations #polynomials #prealgebra #polynomialequations #numbertheory #diophantineequations #comparingnumbers #trigonometry #trigonometricequations #complexnumbers #math #mathcompetition #olympiad #matholympiad #mathematics #sybermath #aplusbi #shortsofsyber #iit #iitjee #iitjeepreparation #iitjeemaths #exponentialequations #exponents #exponential #exponent #systemsofequations #systems
#functionalequations #functions #function #maths #counting #sequencesandseries

#algebra #numbertheory #geometry #calculus #counting #mathcontests #mathcompetitions
via @YouTube @Apple @Desmos @NotabilityApp @googledocs @canva

PLAYLISTS 🎵 :

Рекомендации по теме
Комментарии
Автор

I proceeded as in method 2 but in a slightly different way. Adding the two equations gave me (a+d)(b+c)=11 and subtracting gave me (a-d)(b-c)=1
The second factorization gives: a-d=1 and b-c=1 or a-d=-1 and b-c=-1 thus a=1+d b=1+c or a=-1+d b=-1+c. substituting into the first factorization
gives two equations (1+2d)(1+2c)=11 and (-1+2d)(-1+2c)=11. Factors for 11 are [11, 1] [1, 11] [-11, -1] [-1, -11] so each of the these two equations
gives four answers for c and d from which a and b can be calculated using either a=1+d b=1+c or a=-1+d b=-1+c. In total we have 8 solutions sets
(a, b, c, d) as follows (6, 1, 0, 5) (1, 6, 5, 0) (-5, 0, -1, -6) (0, -5, -6, -1) and (5, 0, 1, 6) (0, 5, 6, 1) (-6, -1, 0, -5) (-1, -6, -5, 0). Finally I think the formulas for c and d given
in the first method are off. For example a=6 b=1 c=0 d=5 is a solution. Method 1 gives c=(6a-5b)/(a^2 - b^2)=(6*6 -5*1)/(36 -1) = 31/35.

allanmarder
Автор

Why are you not speaking ? I personally liked the "only voice with no bgm" vibe in your videos 😅

Venu_GD
Автор

There is a problem, I think the correct answer is A=6, B=1, C=0, D=5...what do you think. ;-)

augusterivoire
Автор

Thumbs up for bluesy jam music. Maybe change up the audio on different videos? (And wishing your voice comes back "2u".)

Qermaq
Автор

In the second method, I see that the letters are in a different order than originally written.

scottleung
Автор

Syber did a problem in which f(f(x)) =x^2 -x + 1. We were to find f(0). Syber did not find f(x) to solve the problem, but how does one find f(x)? The order of the composite is the square of the order of the original function. But if the order of the composite is not a perfect square, how do we find f(x) as in the above example? This seems like an easy problem but I cannot find f(x). If it is worthy can Syber do a video showing how to find f(x) ?

jonathanward
Автор

Answers may be 1, 6, 5, 0 or 0, 5, 6, 1 in order.

SrisailamNavuluri
Автор

There are 4 variables, but only 2 equations.

SweetSorrow
Автор

Thumbs-down on the video for you not speaking and also for that music playing.

robertveith