Derivative of y = x^x^x #jeemains #derivatives #jee

preview_player
Показать описание

  1. Divine JEE
  2. derivative
  3. derivative of x^y=y^x
  4. derivative of y = (sinx)^x
  5. derivative of x^x^x
  6. how to find the derivative of y = (sinx)^x
Рекомендации по теме
Derivative of y=x^x^x 0:06:26

Derivative of y=x^x^x | logarithmic Differentiation #derivatives #jonahemmanuel #excellenceacademy

the most fun 0:05:28

the most fun derivative of x^x^x^...

Derivative of x^x^x 0:11:46

Derivative of x^x^x - Logarithmic Differentiation of Exponential Functions

Implicit Differentiation 0:11:45

Implicit Differentiation

Derivative of x^x 0:03:02

Derivative of x^x

find the derivative 0:00:44

find the derivative of y = x*sqrt(x)

Derivative of xy 0:01:46

Derivative of xy

derivative of x^y=y^x, 0:05:02

derivative of x^y=y^x, implicit differentiation , calculus 1 tutorial, AP calculus

x^2+y^2=(z-c)^2Tan^2α forming PDE 0:15:54

x^2+y^2=(z-c)^2Tan^2α forming PDE by eliminating arbitrary constants #PDE L1k,133

derivative of x^x 0:07:54

derivative of x^x

How to find 0:05:06

How to find the derivative dy/dx for y^x=x^y (calculus 1 tutorial logarithmic differentiation)

Implicit Differentiation 0:14:34

Implicit Differentiation

Derivative of y 0:00:44

Derivative of y = xlnx - x

Difference Between Partial 0:01:44

Difference Between Partial and Total Derivative

derivative for e^(x/y) 0:05:24

derivative for e^(x/y) = x - y, calculus 1 tutorial

derivative of x^(1/x), 0:09:51

derivative of x^(1/x), calculus 1 tutorial

find the derivative 0:00:34

find the derivative of y = (4x-1)^3

Derivative of e^xy 0:03:37

Derivative of e^xy (Implicit Differentiation) | Calculus 1 Exercises

Introduction to Logarithmic 0:13:31

Introduction to Logarithmic Differentiation

Derivative of y 0:00:47

Derivative of y = x^x^x #jeemains #derivatives #jee

y = x^3e^x, 0:00:40

y = x^3e^x, find the derivative

Find the Derivative 0:05:01

Find the Derivative of y = 2x*sqrt(x^2 + 1)

Differentiation by First 0:10:58

Differentiation by First Principle Method | Derivative #jonahemmanuel #excellenceacademy

How to find 0:01:24

How to find the derivative of square root of x (steps)

Комментарии
Автор

By taking log both side
our equation becomes:-
ln(y) = xlnπ
then diff. both side w.r.t x
=> 1/y dy/dx = lnπ
=> dy/dx = π^x lnπ

So, π^x lnπ is the answer 🙂

mrsivasa
Автор

1/y×dy/dx = x/π +π

Dy/dx =y(x/π +π) ❤❤

Logicaltube
Автор

The answer is (π^x. ln π)Take logarithm ( natural logarithm on both sides) of the expression y = π^x
We get : ln y = ln π^x
By using the properties of logarithmic function, we get -
ln y = x ln π
Differentiate both sides -
d/dx ( ln y) = d/dx ( x ln π)
By applying chain rule ( as the variable is y) to LHS, we get
(1/y) dy/dx
By applying product rule to RHS, we get- x. dy/dx ( ln π) + ln π. dy/dx (x)
= x. 0 + ln π. 1
( Since ln π is a constant, it's derivative= 0)
= ln π.
So R.H.S = ln π.
Now proceeding with the previous equation, we have
(1/y) dy/dx = ln π
=> dy/dx = y (ln π)
We know that y = π^x
So substituting y with it, we get,
dy/dx = π^x (ln π)
So, derivative of π^x = π ^x ( ln π).
Thank you sir😊

swetapadmamahapatra
Автор

Homework question answer -
Taking log,
lny = xlnπ
Differentiating W. R. T x:
dy/dx = π^x[lnπ + x/π]

aayushjawalekar
Автор

Home work Question karke mja aa gya sir😀

Jashankaur
Автор

Sir mein abhi class 10th mein hu mujhe abhi konse konse chapters padhne chahiye maths ke jisse meri 11th mein problem nahi aaye .

the.adityayadav
Автор

Accha sir tell me differentiation of x^e^logx

SmilingMathEquation-dqoq
Автор

Bhaiya im in class 8 and ofcourse I cannot understand this, and I want to do IIT... where shld I start frm?

-EArnavSingh
Автор

8:08 Ma’am mera sirf hindi weak hai mai kya karu

Gamingzone_