A Non-Standard Equation | Math Contests

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As you showed by each function (1/2)^x or 2^(-x) is a decreasing function meeting with the linear line functiom (1)(x + 6) that increases in the same intervals. The play with W Lambert function on the ratio to the power eaualling the linear line was interesting! ☺️👍

lawrencejelsma
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I was glad to see you work out what W(n) was without Wolfram Alpha. With x being an integer, I knew there had to be a way.

One thing about how my brain works: I would have just divided ln16/ln2 = log_2(16) = 4. Probably because I never knew about being able to move log down until I started warching your videos. I passed freaking Calculus without ever using ln(2^x) = xln2.

ZipplyZane
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I found x=-2 and it is the only one solution because y=x+6 is an increasing funcion while y= 1/2 is a decreasing funcion

mcumer
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A Non-Standard Equation: (1/2)ˣ = x + 6; x = ?
(1/2)ˣ = 1/2ˣ = x + 6, 2ˣ(x + 6) = 1; x < 0
Solving the exponential equation using Trial-and-error math:
x = – 1: 2ˣ(x + 6) = (– 1 + 6)/2 = 5/2 > 1
x = – 3: (– 3 + 6)/8 = 3/8 < 1; – 1 > x > – 3
x = – 2: 2ˣ(x + 6) = (– 2 + 6)/4 = 1; Proved
Answer check:
(1/2)ˣ = x + 6; Confirmed as shown
Final answer:
x = – 2

walterwen
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X=-2....is the only solution...
Verified graphically

sunny_
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Most important lesson here: manipulate equations but NOT people 🤗😔

marwansal