A Tricky Algebra Challenge | Can You Solve?

A Tricky Algebra Challenge | Can You Solve?

Welcome to InfyGyan!

In this algebraic video we will be solving a tricky rational equation in an easy-to-understand way, making this video an excellent resource for beginners looking to build a strong foundation in algebra. This video breaks down complex concepts into manageable steps, ensuring viewers can confidently tackle rational equations with newfound ease.

Watch as we break down the steps to solve this equation, providing clear explanations and tips along the way. Whether you're a math enthusiast or a student aiming to excel in Olympiad competitions, this video will help you understand and master rational equations.

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In this tutorial, you'll learn:

1- Fundamental concepts and definitions of algebraic equations
2- Step-by-step methods to solve rational equation
3- Common pitfalls and how to avoid them
4- Expert tips and tricks for solving problems quickly and accurately
5- Practice problem with detailed solutions

Additional Resources:

#matholympiad #rationalequations #mathtutorial #substitution #math #mathskills #learnmath #education #algebra

Join us as we unlock the secrets to excelling in rational equations and take your Math Olympiad prep to the next level. Don't forget to like, subscribe, and hit the bell icon for more Math Olympiad prep videos. Let's conquer this equation together!

Thank a lot for watching videos!!

[RashmiRay-cy]

Let y=x+1. Then, 80y^3-y+1=0. The only real root is y=-1/4. Hence x=-5/4.

[StaR-uwdc]

Let t=x+1
80t³-t+1=0
(4t+1)(20t²-5t+1)=0
t=-1/4, t=(5±i√55)/40
x=-5/4, x=(-35±i√55)/40

[Quest]

Let x+ 1= a eqn 80a^3-a+1= 0 or( 4a+1)(20a^2-5a+1)= 0 or a= -1/4 or real x= -5/4 only.

[RealQinnMalloryu]

{x+x ➖}/(x^3+3)=x^2/3x^3 x^2/1x^1 x^2/x^1(x ➖ 2x+1) .

[Fjfurufjdfjd]

Πρεπει χ=/-1. Θετω χ+1=α=/0 και εχω:
(α-1)/α^3=80. 1/(α^2)-1/(α^3)=16+64
(1/α)^2-4^2=4^3+(1/α)^3
(1/α -4)(1/α +4)=[(1/α)]^3+4^3
[(1/α) +4][(1/α)^2 -(5/α) +20]=0
....χ=-5/4 ή χ=[-35-i(55)^(1/2)]/40 ή
χ=[-35+i(55)^(1/2)]/40

[gregevgeni]

x = -5/4
x+1≠0 => x≠-1.
x/(x+1)³ = 80 => 80(x³+3x²+3x+1) = x =>
80x³+240x²+239x+80=0 <=>
(4x+5)(20x²+35x+16)=0 =>
4x+5=0 or 20x²+35x+16=0.
X= -5/4 real solution.