Use THIS Equation To See If You're Attractive (Golden Ration)

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I used this equation and it told me that I’m ugly.

Amzyy
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Okay guys here is a summary
01:53 a guy's beard.
02:18 your body.
03:20 manscappping.
05:38 your glasses.
06:18 your hairs.
And yeah ad ends at 05:37
It only costs a like guys 🔥🔥

nadeemakhtar
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So nobody's gonna talk about the "Golden Ration" in the title instead of "Golden Ratio"

satvik
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Me:*has no school because of the coronavirus*

Jose: use this equation

Me: O gOd NoT mAtH

vaab
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The equation is wrong.
A+B/A would always be greater than one and A/B would always be less than one.

MrHarsh
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*I have the golden ratio!*
Also, I'm bad at math, I might have just calculated it wrong.

rahulpg
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Great. Now I know scientifically and mathematically that I'm ugly.

enricomainenti
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Jose the type of zuniga to make pythagorean theorem part 2 to look good

Alphae
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1) beard
2) body
3) man scape
ad 5:38
4) glasses
5) hair

sbusisosikhosana
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If I had paid this much attention in my class, I would have be in Harvard😂😂

dphellsalami
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Bro what's up with the audio quality nowadays.. it's hard to listen!

suvranildebgupta
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omg, looked through all the comments and nobody mentioned that equation can be valid only if a>b (but not the way it has been shown on the title screen). So I suppose you all deserve to be taught math by fashion vlogger)

lusoyim
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7:10
Jose: “It’s great being a guy”
Feminist: *I’m about to end this mans career*

matalatta
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Jose is a type of zuniga who teaches math in his fashion class

fact_and_facts
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(A+b)/a is always going to be >1 and a/b will always be <1. Unless you’re deformed.

robneuweiler
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Your more relaxed way of speaking in your videos lately makes you more sypathic in comparison to your older videos in which you were talking a way too exagerated and overly excited manner

janj
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Timestamps
1) Your beard : 1:53
2) Your body : 2:27
3) Manscaping : 3:21
Ad 5:38
4) Your glasses : 5:40
5) Your hair : 6:19

mlchaelz
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So the thumbnail has misplaced A and B in the face

madscientixx
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I wear true religion clothes, silver chain, hard part in hair, I think I’m ok...



Idk why people keep sayin I look like a fuccboi🤔(like honestly)

hayden
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a+b/a =/= a/b for all a, b in natural numbers (i.e. every integer greater than 0). This can be easily proved by contradiction. Consider that a=30, b=15, (picked arbitrary), then a+b/a in this case would be 30+15/30 = 1.5. Our a/b would be 30/15 = 2. Therefore we have shown that in this scenario, a+b/a =/= a/b, which suffices to show that this equation does not hold and that we have proven that a+b/a =/= a/b.

mike