In the figure a stone is projected at a cliff of height

In the figure, a stone is projected at a cliff of height h with an initial speed of 42.0 m/s directed at an angle θ_0 = 60.0° above the horizontal. The stone strikes at A, 5.50 s after launching. Find (a) the height h of the cliff, (b) the speed of the stone just before impact at A, and (c) the maximum height H reached above the ground. Use g=9.80 m/s^2.

[banditheeler]

Thank you so much for walking me through this problem!

[taylorlehto]

The world needs more people like you, wanna do my physics midterm for me?

[abdulrahmanmohammad]

Thanks for your efforts, But why don’t we use the first equation for the second branch of the question and the answer will be -17.5 ?

[gaminghero]

Thank you so much, I wish you the very best. You helped me a lot.

[gabe]

Why would they include the negative sign of g into the projectile motion equation? Doesn't that just make it more confusing?

[thatpenguinate]

God forbid my phys teacher teach like this :(

[rawdhahshgroon]

There is another formula to solve part b and why we use this formula. Thank you

[benjamincook]

1323 makes no sense i worked it ou like 20 times and i have gotten 1323