Viral Maths Equation 6/2(1+2) Only For Genius - Maths Puzzles

preview_player
Показать описание
What Is 6÷2(1+2) = ? The Correct Answer Explained

The problem has generated debate and has millions of comments on Facebook, Twitter, YouTube and other social media sites.
This Viral Maths Equation is getting popular around the social media, and has left everyone confused. To solve this maths puzzle equation, hint is to use BODMAS.

You will love to watch our popular videos:
1. Fill The Boxes Using 1, 3, 5, 7, 9, 11, 13, 15 - Gaurav Agarwal's IAS Exam Question

2. Only 1 Out of 7 Will Get This Right Cookie Banana Maths Puzzle Answer

3. How can we get 60 by adding only three numbers | 2 6 10 14 Total 60 Answer

4. I had 3 dollars riddle answer - Riddles that will trick your mind

5. Hen, Eggs and Bananas Puzzle - Only for Genius

6. Clock, Calculator and Bulb Puzzle - Viral Maths

7. Shoes, Boy and Popcorn Puzzle | Shoes Ice Cream Man Puzzle Answer | Only For Genius

-----------------------------------------------------
For Business inquiry, Please reach out to us at:

➤Puzzle Adda:

➤Facebook:

➤Twitter:
-----------------------------------------------------
#PuzzleAdda #Puzzle #OnlyForGenius
Рекомендации по теме
Комментарии
Автор

The purpose of PEMDAS and BODMAS is to simplify the expression so that multiplication, division, etc, can be more easily done.
In the case of 6÷2(1+2), we have two terms, 6 and 2(1+2) and a single operation, division. (÷).
It is important to remember that even though a x b = ab, the single value ab = (axb) .
If we want to change 6÷2(1+2) from implicit to explicit multiplication, by adding the (x) sign between 2 and (1+2), like this 6 ÷ 2 x (1+2), we must add an additional set of brackets, as well, like this 6÷2(1+2) = 6÷(2 x (1+2)).

Thus
6÷2(1+2)=
6÷(2x(1+2))=
6÷(2x(3))=
6÷6=
=1

alternatively, apply the distributive law.
6÷2(1+2)
6÷(2+4) Distributive law, a(b+c) = (ab+ac) or (2x1+2x2) = (2+4)
6÷6
1
alternatively, apply the division operation two both factors 2 and (1+2)
6÷2(1+2)=
6÷2÷(1+2)= Division by a product= division by its factors
3÷3=
1
alternatively, we can write the problem vertically

6 6 6
= =1
2(1+2) 2+4 6

for those who insist on dividing 6 by 2 first, we can do it this way:.

6 6 x1 6 1 3 1 3
= = x = x = = 1
2(1+2) 2x(1+2) 2 (1+2) 1 3 3

Again, It is important to remember that even though a x b = ab, the single value ab = (axb) .
6 ÷ 6 does not equal 6 ÷ 2 x 3, it equals 6 ÷ (2x3), and in this case, 6÷2(1+2) = 6÷(2x(1+2))

dgkcpa
Автор

6÷2x(1+2)=9
6÷2(1+2)=1
You changed the question when you changed "2(" to "2 x "
Either the "correct" answer is 1 or both answers can be accepted. 9 is not THE correct answer.
The vast majority of the world disagree with 9 and America, one of a very small number of countries who believe Juxtaposition doesn't exist, is one of the youngest countries in the development of mathematics so please don't assume you youngsters know best.

neilmorgan
Автор

The expression is ambiguous due to the notation used.

There is no agreed upon convention on whether multiplication by juxtaposition implies grouping or not .

I.e. does 2(3) = (2×3) or 2×3?
Both are widely used so both are valid.

6÷(2×3) = 1.
This is the more academic interpretation using implicit notation
6÷2×3 = 9
This is the more programming interpretation using explicit notation.

It's simply a badly written expression written this way on purpose to be misleading and go viral.

No mathematician, scientist or engineer worth their salt would ever write like this.
It would be
6/(2(1+2)) for 1 or
(6/2)(1+2) for 9.

It's as bad as writing Sin60/2, 16/8/2, 2^3^4 or "A union B intersection C" in sets.
Another set of brackets are required to make this question legitimate and have only one valid answer.

Modern international standards like ISO-80000-1 mention about division on one line with multiplication or division directly after and that brackets are required to remove ambiguity. ISO-80000-2 says the ÷ symbol shouldn't be used.

There is a paper on this ambiguity by a PhD student called the PEMDAS Paradox which talks about this problem.
Other places to read about both sides of the argument are:
- Ambiguous PEMDAS Harvard
- Slate PEMDAS
- Wolfram Alpha's Solidus article
- Bracketing Mathematical Expressions H9
- PEJMDAS by the How and Why of Mathematics

There is no single answer to this expression.

GanonTEK
Автор

The answer here is wrong. It should be 1. Parentheses first. And you don’t remove the parenthesis once you perform the math operation within the parentheses which is where you went wrong. PEMDAS exists for a reason

ThatDudeTonyB