Calculus 3.2 Maximum and Minimum on an Interval

We use the algorithm of taking the derivative and finding where the slope = 0 in order to find max and min values but on an interval we must ALSO test the end points of the given interval.

[calculusisamazing]

This is amazing, it makes calculus so much easier. You've changed so many lives for the better. Bless you!

[PizzaTimeLover]

Greetings Miss, How exactly did you know to use f(1) and f(-1) to find max and min? was it because it was when dervitive equalled zero? In addition why was f(-2) used? Thank you :)

[Hasaann]

ms havrot at the part when you check the function, why do you use those x values to check it?
also, when you have the interval as xe(x, y) then what do you do?

[gracityboonchoy]

Thank you for a great lesson on this topic

[delinakaleab]

I just finished solving question 4.e) and from I see I did it correctly, but for 4.f) with the same function, how does the chain in domain not include (1, 2) and (-1, -2)?

[sivathiyagarajah]

Hey Ms, do you have a video on related rates? I know it isn't in the textbook but my teacher is going to include related rates on our chapter 3 test

[moski]

Hello Ms Havrots, I am a little confused, At 6:25, why is the minimum value -2 and not -8/5? -8/5 is lower than -2 so wouldn't that be the minimum value? Thank you!

[utqx]

Why can't you just do f(+-1) because that's your max/min as defined by f'(x) = 0. Why f(-2) and f(4)?

[wajdy]

5:47 why do you do f(-2) and +-1 but not 4?

[vyn]

Hi Miss
What if I have two max and they are the same value?
Thank you

[sarag]

did this video used to be 13 minutes long?