how to fix Value Error: invalid literal for int() with base 10

Are you getting how to fix Value Error: invalid literal for int() with base 10 and wondering what it means and how to fix it? I recently had to solve this problem and was not understanding exactly what was going on. Invalid literals can be relatively easy to fix once you understand why it is happening, this video helps you figure out the problem and then shows how to fix it.

⏲⏲⏲TIMESTAMPS⏲⏲⏲
Beginning 00:00
Integer Properties: 00:22
Error Explanation and fix: 00:44
Error Explanation with input and fix: 03:15

################ Let's be Social! ##################

#ValueError #invalidliteral #dataanalytics #dataanalyticsireland #base10

[nathathorn]

This helped me with my college assignment! Thank you :)

[BrandonJacobson]

Yes! Troubleshooting videos are the best.

[mohitpatel]

I want to compare 2 characters. Like 'b' and 'c'. So how do I do it?

[cocichan]

Hello bro, i get this problem when i was bitcoin key compression tool :
invalid literal for int() with base 16:''
How i can fix this problem

[rithinkumar]

a = int(input("enter a number :"))
print (a)


input = 3
ValueError: invalid literal for int() with base 10

I am getting this error in VScode how to resolve this

[tanmaykumar]

What shortcut you used to comment out the line very fast??

[vitorangheben]

How do I fix this problem with a try, except loop?

Tks for now!

[gamingprince]

Why am i getting this error even after typecasting a string in to an integer

[kanikasharma]

#prime number
n=int(input('enter number : '))
print(n)
print(type(n))
factor=0
i=1
while(i<=n):
if (n%i==0):
factor=factor+1
i=i+1
if (factor==0):
print('it is prime number')
else:
print('it is composite number')




Can you help me with this code please....

[anthonydickens]

code is
player_1_age = " "
player_1_age = input("What is your age ? ")

**run script**
#customer replies 37
ValuEnnor: invalid literal for int() with base 10: ' '

fix ?
player 1_age_int = int(player_1_age)
error: ValuEnnor: invalid literal for int() with base 10: ' '

also tried...
player 1_age_int = int(float(player_1_age))
error: could not convert string to float : ' '

[mateochauque]

Hi, what a great video! Thanks, I understood what you put but I don't know how to change it so that it comes out correctly.... look I have a problem with the whilee! I could help me to know that I have failed?

mport os
os.system('cls')

number = int(input('Enter a number from 1 to 3: '))
if 1< number >3:
print('It is not 1, 2 or 3')
if number == 1:
print('One')
if number == 2:
print('Two')
else:
print('Three')

continue = int(input('You wish to continue y/n: ')))
while continue == 'y':
print(number)

[sneha.tiwari]

Hey, anyone knows here how to deal with this error??

invalid literal for int() with base 10:

I'm using sorted function in this manner
sorted(os.listdir(BLOCKCHAIN_DIR), key = lambda x: int(x))

[prathamsinha]

"""Write a python program for inserting employee data
Employee No. and Name and deleting employee details from
employee stack.
"""
Employee=[]
c="y"
while(c=="y"):
print("1.PUSH")
print("2.POP")
print("3.Display")
choice=int(input("Enter your choice:"))
if(choice==1):
e_id=input("Enter Employee no :")
ename=input("Enter the employee name:")
emp=(e_id, ename)
Employee.append(emp)
elif(choice==2):
if(Employee==[]):
print("Stack Empty")
else:
e_id, name=Employee.pop()
print("Deleted element is", e_id, ename)
elif(choice==3):
i=len(Employee)
while i>0:
print(Employee[i-1])
i=i-1
else:
print("Wrong Input")
c=input("Do you want to continue or not?")

I am writing this in pydroid ( app from Google play store)
And after entering 1 it says invalid literal for int() with base 10
So is it the apps fault or something is wrong in the code