How to Solve Atomic Structure question in 5 Sec | Atomic Structure Shortcut | Mohit Ryan Sir

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Solve Atomic Structure question in 5 Sec
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Don't let atomic structure questions intimidate you anymore! Join us in this video and unlock the secret to solving them in just 5 seconds. Hit the play button and take a step towards conquering IIT JEE Exam with confidence.
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#Trick 1:-[First ques]
n- given in the ques.
For balmer series:- n-2.
For any series we can use this trick n - ni(lower value of b acc to respective series).
#Trick 2.[2nd ques].
Red has the highest wavelength, by seeing the diagram only we can say tht line 3 to 2 having the lowest energy means highest wavelength.
#Trick3 [3rd ques]
Check num of peak = n- l.
In the figure we can see two peaks and by formula n-l we can say 2s is hving two peaks.
Hence b opt is the ans.
Thank you so much dost ❤
Love uh infinity moles❤️🔥

Simran
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Mere se bhi ho gye in less than 5 sec as 1) qs are easy and 2) concepts are clear. Acc to me this would be beneficial for school and mains only. BTW logic for all

Trick 1 : we are analysing transition of n_higher (from where we start) to n_lower (given final destination, here visible => balmer => n_lower = 2). if we visualize the final transition, each's n_higher decreases by 1 every time (here 6->2, 5->2, ..., 3->2)

Trick 2 : Sir se badia main kya hi exolain karun iss wale ko (my input would be ki if we remember that energy is inderictly proportional to n^2, then its logical, jitna niche transition, utna bada energy gap)

Trick 3 : My method is little different. I count number of times the graph touches the x-axis, so it gives me number of radial nodes, then i have remembered the nodes formula

kabirgambhir
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Sir physical chemistry calculations are vast and almost undoable without calculator. pls show us the way to solve them down completely without using calculator even once. practice isn't bring that skill, pls help

tonishaghosh
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Doubt for 1st question:
Sir, with due respect, Jo aapne answer Diya usme to answer ye bata rha hai ki kitni lines balmer series me fall karengi but mene padha tha ki balmer series me saari line visible region me nhi hoti sirf first four line hi visible region me aati hein. To lines in visible region to kabhi 4 ko extend karni hi nhi chahiye but acc. To your explanation, lets say n=12 and then balmer series me to 12 = 6 lines hongi but visible region to abhi bhi 4 hi honi chahiye na. Kyuki balmer region me sirf starting ki 4 lines hi visible region me hoti hein. Bas agar n≤6 hua tabhi vo formula valid hona chahiye kyuki agar aage ke shell ke liye vo balmer series ki total lines batayega na ki visible region ki

I think ki vo formula number of line in a series ke liye hein but visible range ke liye tab Tak valid hai jab tak n≤6 na ho
Agar n>6 hua to vo number of line in a series ke liye to sahi hoga but visible region me uske baat hmesha 4 line hi aayiengi
Sorry if I said something something bad
Please correct me if I am wrong❤️

shakuntalasingh
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Bonus point for second question: Red light emitted means visible spectrum, i.e. Balmer series, and only one of the lines was reaching n = 2

EDIT: I was mistaken, this is not correct, pls read comments to understand

shauryagupta
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Me center me beth kar ye video dekh Raha hu 💀

PratikHarsude
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Thanks a lot. These videos really do help. Looking forward for more of these kind of videos

rithwika
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Literally dost, these qns gave me confidence
I'm happy that i was able to keep up my pace with u, & also did learn another approach to the same qns
LY3M ❤❤
I'm loving this series 😁

Saxena_Anant
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1 more trick for ques 3rd is that counts only the roots of graph which is equal to radial nodes

hyperxgaming
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Arvind sir, its a request that please bring short cut trick videos of every chapter for jee 2024 aspirants🙏🏻

prathamvashisht
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Sir at the same time you uploaded the video I was revising atomic structure chapter and was in need for such tricke

hemaltrivedi
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Please bring more tips and short type content very helpful ❤❤

Umaidali
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When did Haris Rauf Started Teaching Chemistry 🤯

SPOTLIGHT-dpks
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No. Of spectral line =(n2 - n1) (n2 - n1 + 1)/2

priya__
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While defining no. of unique/visible spectral lines we always rend to forget that sample is given or atom is given... That's the click of the question 🤍🪂

manusinghtiwari
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Amazing sir just amazing 👏
Thank u soo much 🙏🙂

NailaKhans-lnmk
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Dear Mohit Ryan/Arvind Kalia/Tharun Sir, can you please put the English subtitles. I had commented the same in one of your the underperformer IIT JEE Aspirant videos sir. Please sir 🙏🙏🙏🥺.

JEEhemanth
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Sir pls give some shortcut trick for phsi questions

ixzfjsw
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Shouldn't we include the reading time in solving art of 5 sec also😅

jykhhxn
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i had a doubt reagading orbitals, will someone care to explain, so for 2s its meant to represnt the probability density for the second shell right, so why then in its visualization 1s is also included, and then its radial node becomes 1, i mean if its like suppose aluminium for example wont that nodal region also have probability of finding e- because of all the different orientations of p's, someone pls help

lifelinegaming