Sum n!/n^n (Series Direct Comparison Test)

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BriTheMathGuy

Great stuff. I like the way you presented the strategy and the execution of it.

pipertripp

Such a perfect explanation and presentation! Thank you so much for making this video!

craigl

Thank u so much. I love the video and your brilliant presentation. So cool and have fully understood. Thanks once again. Please thanks.

muwongeevanspaul

i dont conceptually understand what n factorial means. Like when you say n(n-1)(n-2)....3*2*1. How can I learn this concept?

stazzeldskater

Actually, we DO know what the 2nd series converges to; it is exactly (π^2)/3. This is because the infinite sum of 1/(n^2) is exactly (π^2)/6, as proved by Euler.
Great video!

alkankondo

1:43 I don’t get it, where does the 3…2…1 come from?
I understand n(n-1)(n-2)(n-3) but how do you get the 3.2.1?

beetogarcia

Kindly explain this one sir I really need it if the question is like this 1/n^n then how we can solve it by direct comparison test my question same like this one but the numerator is 1 in stead of n!

atta

Just use ratio test

Makes more sense

madobat

Or you can use partial fraction followed by integration.

_H_A_R_S_H_I_T_

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