Friction Force | NLM for JEE & NEET | Class 11 #OnionPhysics | Mechanics L-25

Topics covered in Lecture 25 of Friction Force in chapter Newton's Laws of Motion for JEE & NEET in Onion Physics are listed below with timestamps:

Timestamps:
00:00 Friction for JEE & NEET
02:46 Motion of block pulled by boy on rough surface
04:47 Important points about Friction
05:35 Limiting Friction and coefficient of static friction
06:50 Relation between friction and normal reaction
07:36 Concept of Sliding - When does block start sliding?
10:19 Kinetic friction and relation between kinetic and limiting friction
11:51 Graphical representation of Friction varying with external force
13:20 Acceleration of blocks on rough surface in pulley block system
16:20 Tension in strings with friction in pulley block system
17:05 Motion of block on rough surface in pulley block system
20:00 Minimum force required to slide a block on rough surface
21:00 If force is applied at an angle, minimum force required to slide a block on rough surface
23:46 Angle of friction
24:40 Pushing a block at an angle on rough surface such that it does not slide at all
28:46 Acceleration of block sliding over a rough wedge
30:05 Angle of Repose
32:06 Condition of sliding the block on rough inclined plane
33:07 Upward sliding of block on rough wedge
34:42 Acceleration of block wedge system when released from rest on rough wedge

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[prabalsinghsengar]

In just 40 mins explained whole chap in depth

[offline]

It is all a student needs to know about friction ! Thank you very much sir ..you are a blessing to this generation

[adityajha]

Homework 1
Soln:- accn of block × cos theta=aacn of wedge x sin theta
The above result is given by using constraint relation
accn of block =gsin(theta)-gcos(theta)
And aacn of wedge will equal to cot(theta) x aacn of block

[mrunknown]

Sir at 18:23, aapne velocity le liya hai but questions me acceleration diya hai,
Then the on solving I'm getting a=5/7 m/s² please correct me if I'm wrong

[thechrist]

36:25 a2= g sin(theta)- eta g cos(theta)
a1= (g cos(theta) sin(theta))/2

[sushmabhajangeetbela]

For H.w 2,
Frictional force=pseudo force
f L = F
uN= ma
0.2×20=2a
4=2a
a=2m/s²

Therefore, F req.= M total × accn = (5+2)×2= 14 N

(Please verify if it is correct or not)🙏

[adityabhardwaj]

19.50 sir there is velocity given or acceleration? 2 m/s²

[MeetAgarwal]

24:28 ans is ∆mg/√1+∆sq.
Wherw ∆ = cofficient of friction (mu)

[nitin]

HWIL-1
net acc.. of block =
acc. of wedge =

HWIL - 2
F(min)=14N

[yagyaparasar]

Sir plz explain friction between pulley and string case...that is little complex in your book

[kingkong]

This is very helpful for those students who have been clear thier concept . other wise they think that it is out of syllabus

[sayantandas]

I think he is much better than physics wallah . He is genuinely intellectual.

[sreekanchi]

sir could you please make onion physics lectures on electic chapters also

[LEGENDARY-P.M]

17:55
who had noticed that sir had taken unit of velocity incorrect.

BTW Awesome explanation

[sagnikmukhopadhaya]

Thanks sir for these lectures. Very short and to the point.

[Balkrishna_Bhardwaj]

Can anyone please explain At 33:29 Upward sliding mean?

[rmishra]

a1 is

[mg sin(theta)cos(theta) - myu mg cos square (theta)] / { M + mSin square (theta) - myu m in (theta) Cos(theta) }

Now a2 can be calculated very easily but it was too complex to write

[anikmukherjee]

17:35 ye kiya hua?? velo city ar accn ki golmal ho gaya...ku6 samajh nehi aya

[abhimodanwal]

Thank you so much sir for this knowledge 🙏🙏🙏🙏

[TWICK-X]

Sir, you are focusing more on theory, as all of us know, THEORY IS POWER.🥵❤