Class 11 chap 5 | Friction Force 03 | Block on Block Problems Friction | IIT JEE / NEET

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App.

LAKSHYA Batch(2020-21)

Registration Open!!!!

What will you get in the Lakshya Batch?

1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey.

2)Live Classes and recorded Video Lectures (New, different from those on YouTube)

3)PDF Notes of each class.

4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.

5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.

6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)

7)In case you missed a live class, you can see its recording.

8)You can view the videos any number of times.

9)Each chapter will be discussed in detail with all concepts and numericals

10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.

****Test Series for XI & XII****

We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.

Class 11 chap 5 || Friction Force 01 ||Static and Kinetic Friction || Friction IIT JEE / NEET ||
Class 11 chap 5 | Friction Force 02 | Angle Of Repose | Friction on Inclined Plane | IIT JEE / NEET
Class 11 chap 5 | Friction Force 03 | Block on Block Problems Friction | IIT JEE / NEET
Class 11 Chap 5 || Laws Of Motion 01 || Newton's First Law Of Motion || NLM IIT JEE NEET NCERT
Class 11 Chap 5 || Laws Of Motion 02 || Newton's Second Law Of Motion || NLM IIT JEE NEET NCERT
11 Chap 5 || Laws Of Motion 03 ||Pulley Tricks For IIT JEE Mains || How To Solve Pulley Problems
11 Chap 5 || Laws Of Motion 04 || Newton's Third Law Of Motion ||Conservation Of Momentum
11 Chap 5 || Laws Of Motion 05 || Spring Force || Spring Numericals|| JEE mains NEET All concepts
11 Chap 5 || Laws Of Motion 06 || Pseudo Force | Inertial and Non-Inertial Frame of Refrence IIT JEE
11 chap 4 || Circular Motion 06 || Motion in a Vertical Circle IIT JEE / NEET || Critical Velocity||
Motion Under Constraint || IIT JEE MAINS and NEET Physics || KINEMATICS Class 11 / JEE /NEET ||

[PhysicsWallah]

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App.



LAKSHYA Batch(2020-21)

Registration Open!!!!

What will you get in the Lakshya Batch?

1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey.

2)Live Classes and recorded Video Lectures (New, different from those on YouTube)

3)PDF Notes of each class.

4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.

5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.

6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)

7)In case you missed a live class, you can see its recording.

8)You can view the videos any number of times.

9)Each chapter will be discussed in detail with all concepts and numericals

10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.


****Test Series for XI & XII****

We provide you the best test series for Class XI, XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.

Class 11 chap 5 || Friction Force 01 ||Static and Kinetic Friction || Friction IIT JEE / NEET ||
Class 11 chap 5 | Friction Force 02 | Angle Of Repose | Friction on Inclined Plane | IIT JEE / NEET
Class 11 chap 5 | Friction Force 03 | Block on Block Problems Friction | IIT JEE / NEET
Class 11 Chap 5 || Laws Of Motion 01 || Newton's First Law Of Motion || NLM IIT JEE NEET NCERT
Class 11 Chap 5 || Laws Of Motion 02 || Newton's Second Law Of Motion || NLM IIT JEE NEET NCERT
11 Chap 5 || Laws Of Motion 03 ||Pulley Tricks For IIT JEE Mains || How To Solve Pulley Problems
11 Chap 5 || Laws Of Motion 04 || Newton's Third Law Of Motion ||Conservation Of Momentum
11 Chap 5 || Laws Of Motion 05 || Spring Force || Spring Numericals|| JEE mains NEET All concepts
11 Chap 5 || Laws Of Motion 06 || Pseudo Force | Inertial and Non-Inertial Frame of Refrence IIT JEE
11 chap 4 || Circular Motion 06 || Motion in a Vertical Circle IIT JEE / NEET || Critical Velocity||
Motion Under Constraint || IIT JEE MAINS and NEET Physics || KINEMATICS Class 11 / JEE /NEET ||

[nupur]

My one advice to everyone please watch this lecture once again after sometime then, you will surely understand the concepts clearly, as this is among one of the complex topics so many can't understand it at first

[rajshah]

at 29:54 I think you need to take the friction coefficient between 10kg block and ground as 0 instead of 0.1 as you havent considered that in the question.
Anyways awesome explanation sir, I love watching your videos👍

[swityyadav]

Happy teachers day to one of the most amazing teacher

[gametech]

Sir, you are really one in 'A LAKH', You are just GREAT!

[shashiraj]

28:38 Fmax changes, because now in this question lower block also has Friction coefficient, but in previous question lower block don't have any friction coefficient, so Fmax changes

[aryanverma]

For everyone who got confused in 28:08 question
Sir made a mistake instead of writing 0 sir wrote 0.1 so fmax wouldn't change as when he made the 10kg fbd he considered friction of 10kg be 0
So don't get confused

[cppandey]

Physics wallah : like
Unacademy : comment

[flypheonix]

I have watched this lecture 1 time and understood almost 60% and I will come again to understand more..

[vercotiseredemption]

Alakh sir exactly knows the mindset of the students. I have never come across someone with teaching experience as good as alakh sir . You really have raised every bar of teaching any teacher could possibly have set.

[Diiacreahsi]

28:00 mint waale sawaal mein galat hai sir, 15 N not max force for that because their is friction0.1 between lower block and surface where as in previous questions there was 0 friction between lower block and surface..

[akashP]

Sir apke videos dekh dekh k mene class test top Kia chemistry ka

Kisi ne b expect nhi Kia tha (kyonki m koi tution b nhi jata)


Thank you sir 😍

[sakshamsharma]

I love sir's accent while sayin *"aksleration"*

[ankushroy]

amazing hai yaar yeh video kya video hai bhai maan gaye alakh sir is the best

[jashansidhu]

I am really luck that i born in that generation where physics wallah is there 😍😍 thanku sir

[sakshim.]

Sir not only this one..but all of your lectures are BEST among other on youtube..😃

[gauravahirwar]

The Man behind our success in the exams ❤️❤️

[ritulranjan]

Amazing sir i regret that i found ur channel very late

[yashjoon]

Let me clear the confusion at 28:00 problem just to help people as I was also confused at the starting
Look value of limiting friction on 10 kg block due to 5 kg block is given by u N = 0.2 * 5 * 10 = 10 N.
Now limiting friction on 10 kg block due to ground is : u N = 0.1 * (10+5) * 10 = 15 N
Now closely analyse the system and see that friction due to ground is higher than friction due to 5 kg block . thus the 10 kg block wouldn't move at all, at any force applied on 5 kg block. Hence 10 kg would remain at rest and acceleration of 10 kg block would be 0. Now to find acceleration of 5 kg block make FBD. On making FBD we get friction force backward as 10 N and applied force forward as 50 N
Thus net force in forward direction becomes 40N and a=f/m thus a=40/5 = 8m/s^2

[anveshasrivastava]

Sir you are the best teacher I have ever seen. Even my physics teacher also sees your video and recommend us to do the same. My physics teacher also teaches very well but your teaching is magical sir.
Sir aapme jadu hai jadu :-)