Trick : 2 Block Problem In 10 sec | Friction Class 11 | IIT JEE & NEET | ATP STAR | Surya sir

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Solve Any two Block Problem In 10 sec | Friction Class 11 | JEE/NEET | ATP STAR

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🔴𝐒𝐮𝐛𝐬𝐜𝐫𝐢𝐛𝐞 𝐭𝐨 𝐎𝐮𝐫 𝐎𝐭𝐡𝐞𝐫 𝐂𝐡𝐚𝐧𝐧𝐞𝐥𝐬 -
➤𝐀𝐓𝐏 𝐒𝐓𝐀𝐑 𝐂𝐥𝐚𝐬𝐬 𝟗 & 𝟏𝟎 :
➤𝐀𝐓𝐏 𝐒𝐓𝐀𝐑 𝐂𝐡𝐞𝐦𝐢𝐬𝐭𝐫𝐲 :
➤𝐀𝐓𝐏 𝐒𝐓𝐀𝐑 𝐏𝐡𝐲𝐬𝐢𝐜𝐬 :
➤𝐀𝐓𝐏 𝐒𝐓𝐀𝐑 𝐌𝐚𝐭𝐡𝐬 :
➤𝐀𝐓𝐏 𝐒𝐓𝐀𝐑 𝐁𝐢𝐨𝐥𝐨𝐠𝐲 :

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🟢𝐅𝐨𝐥𝐥𝐨𝐰 𝐮𝐬 𝐨𝐧:

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𝐎𝐮𝐫 𝐄𝐦𝐚𝐢𝐥: 𝐬𝐮𝐩𝐩𝐨𝐫𝐭@𝐚𝐭𝐩𝐬𝐭𝐚𝐫.𝐜𝐨𝐦
𝐂𝐨𝐧𝐭𝐚𝐜𝐭 𝐔𝐬: 𝟎𝟖𝟎𝟒𝟕𝟒𝟖𝟒𝟖𝟒𝟕

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[deepphasejuniorgamerz]

In First Case
A1 = 2
A2 = 9
In Second case
A1 = 18
A2 = 1
All in. SI unit m/sec square

[roseleen]

Thankyou so much sir. Bohot dikkat ho rhi thi ye smjhne me...aapne bht ache se smjha Diya sb ❤

[NaveenKumar-fvwn]

Nice concept sir ...please. Continue this series

[sayakhdas]

1st case ans a1=2m/s*2 & a2=9m/s*2
2n case ANS a1=18m/s*2 & a2=1m/s*2
am i right sir

[DhruvMishra-km]

True and false -
1. The limiting force of static friction depends on area and contact and independent of material
2. The limiting force of kinetic friction depends upon area of contact and independent of material
3. The limiting force of kinetic friction is independent of area of contact and it depends on material
4. The limiting force of static friction is independent of area and contact and depends on material.
5. Both limiting friction and static friction depends on area of contact and nature of material

[Chethana_]

In first case
a1 = 2 m/s² and a2= 9m/s²
In second case
a1= 18 m/s² and a2= 1 m/s²

[ArzooSharma-zs]

Thanku so much sir
It's very hard topic for me but i did 30 ques of it one by one most easily. It became very easy now

[falakkhan]

Thank you Sir... Its really worth it❤❤❤

[SampathRaj]

Case 1:
a1=2m/sec sq
a2=9m/sec sq
Case 2:
a1=18m/sec sq
a2=1m/sec sq

[Srishty-ehlj]

Thanks sir was struggling with this one
😊

[AbdullaC-pnzu]

Sir, We give english subtitles, it will help to understand easily by other language people😢😢😢😢😢😢

[Mr.RamingtoN]

Thanxxx a lot guru g bahut dikkat hoti thi in question me aapne samjha dya ab ye question apni aukat me rahega

[varshasaini]

Thnks sir...aaj exam.h muze ab bhi isme.confidence ni aara tha ab aa gya 😊

[gajaysingh]

Do these questions come in neet as it never came before

[sayakhdas]

sir agar friction ground per ho tab kya hoga ?

[NityaKrishnaDas]

Esliye acceleration ko aukat mai rakha padega taki alag alag na ho 😁

[Nishantkumar-cmlw]

ye trick tha ?
yhe to hum complete process ke naam pe sikhe the
btw revision ke liye thanks

[a_hi]

in second case, Acombined should be equal to (F-f)/m1+m2

[SrushtiDhanwe]

Thank you sir for the simply understanding explanation 😊

[codingbyprabhkiratsingh]

Lecture starts from 1:00
you are welcome