Arithmetic Progression Class 10 Maths One-Shot (Chapter 5) | CBSE Class 10 Mid Term Exams

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In this Mission Mid-Terms series, your favourite BYJU’S Maths teacher, Khushbu Ma’am, teaches important concepts in your class 10 Maths chapter 5, Arithmetic Progression.

An arithmetic progression (AP) is a list of numbers in which each term is obtained by adding a fixed number d to the preceding term, except the first term. The fixed number d is called the common difference. Remember that it can be positive, negative or zero.

In this class, Khushbu Ma’am discusses the following topics in detail:
1. n^th term
2. Sum of first n terms

Ma’am also takes a few minutes to solve a few maths problems related to Arithmetic Progressions to help you understand the concepts better.

Find this class helpful? We have a host of class 10 Maths revision videos and LIVE classes on our BYJU’S - class 9 & 10 channel to help boost your preparation for the upcoming unit test and board exam. Subscribe now to get access to all the videos!

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00:00 Arithmetic Progression Class 10 Maths One-Shot
2:22 ANTHE - Aakash National Talent Hunt Exam
3:33 Mission Mid-Terms
4:22 Cinema
5:03 Q. How many seats are there in the tenth row?
5:59 Common Difference
11:40 nth term of A.P
13:50 Q. How many seats are there in the tenth row?
16:22 Q. What about the total number of seats in the theater?
16:43 Sum of first n terms
28:13 Q. How many total seats are there in the hall?
30:39 Q. Find the total fare for 5 kms.
35:39 Formula Sheet - Arithmetic progression
36:10 General Form of an AP
36:30 Sum of First n Terms in an AP
37:26 Homework Question
38:47 About Telegram

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#arithmeticprogressionclass10oneshot #class10mathschapter5 #mathsarithmeticprogressionclass10 #class10mathsarithmeticprogression #mcqonarithmeticprogressionclass10
#arithmeticprogressionclass10mcqs #arithmeticprogressionmcqs #class10maths #cbseclass10maths #cbseclass10 #cbseclass10midtermexams #class10midterm
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HW:
Gn: n=20, nth term is => an= 5+4n
We need a and d
a1= 5+4(1)
a1 = 9
a2 = 5+4(2)
a2= 13
WKT a2-a1 =d
->13-9 =4 =d
By applying sum of n terms formula,
Sn= n/2[2a+ (n-1)d]
= 20/2[2×9+ (20-1)4]
= 10[ 18 +76]
= 10(94)
= 940
Therefore the sum of first 20 terms is 940 :) ❤

rithizx
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Given an =5+4n
So 20th term = 5+4×20 =85
And 1st term = 5+4×1=9

Therefore, Sn =n/2(a1 +an)
Sn =20/2 (9+85)
Sn =10× 94
Sn=940 ans

ihoonlvr
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Homework question answer is 940
Great session byjus thanks
Hoping soon we will be 100k family....

adityapatil
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Attendance of people who agree that this was one of the best one shot lecture in u tube❤
👇

shrilaxmicshetty
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Am i the only one who get confused an and n😭

shareefabeegum
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Mam make a session based on basic maths for class 10th

likhitha
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31:28 mam why are we not applying the first formula an=a+(n-1)d ?

nahida
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It was crystal clear explanation and i understood the whole concept and now iam able to solve the problems easily
Just amazing!! explanation i understood very well...!!! Thankyou and teach us more like this

mdnayimuddin
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Mam I have a doubt in 25:15 plss explain tht how we get the formula after adding both equations

ayishafaiha
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thank u maam for this fruitfull session

dasKishor
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Thanks Ma'am for amazing again ... Ans of homework question is 940

ramlal
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Mam roots nekhlna me problem hoti hai .can you help me?

kalpanaprakash
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It was actually helpful 💟 thank u so much mam♾️

sowmyap
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I'm watching after 1 month.. and also I understood well thank u mam for ur explanation....

viswasraj-ct
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Mam we r not getting notes in the telegram channel for (pcmb)

asimalvi
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Mam ncert lecture for this one chapter asap pls!🤌🏻

M_tales
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Mam I love byjus classes and I'm am glad to get u as my best math teacher.
Mam can u pls tell us how to understand the questions given I really lack in this 😔 pls help me Mam pls pls 🙏 🙏🙏🙏🙏🙏🙏🙏🙏🙏

jagrathijagrathim
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Mam sum of n terms is 900
Is my answer is correct?

thoutamnavaneetha
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Good morning,
Homework solution:
nth term=5+4n
From this a=5
Sn=n/2(a+l)
Sn=20/2(5+5+4(20)
Sn=10(10+80)
Sn=10(90)
Sn=900
So the sum of first 20 terms given here is 900.

ammulu
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