Arithmetic Progression Class 10 in One Shot 🔥 | Class 10 Maths Chapter 5 AP | Shobhit Nirwan

In this video we'll study class 10th chapter 5 Arithmetic Progression in One Shot !

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Gears I use:
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1) Arithmetic Progression Class 10 in One Shot 🔥 | Class 10 Maths Chapter 5 AP | Shobhit Nirwan
2) Arithmetic Progression class 10 ex 5.1
3) Arithmetic Progression class 10 one shot
4) Arithmetic Progression class 10 ex 5.2
5) class 10 maths chapter 5 exercise 8.1
6) class 10 maths ap
7) class 10 maths ap one shot

Love you all ❤️
Shobhit Nirwan

[ripple.lives-on]

Some corrections-
52:12- It’s 18+1= 19
1:20:00- Last me ans me minus sign bhi lagna hai😅, it’s -979
1:30:29- It’s 7x6= 42

[yooonaaa]

35:38
principle = 10, 000 ; rate of interest = 7%
a=p[1+r/100]^time
a=10, 000[1+7/100]
a=10, 000[107/100]
a=100*107
a=10, 700

[Shivam.me]

Arithmetic Progression (AP) is a sequence of numbers where each term is obtained by adding a fixed number to the previous term. The summary covers the definition, general form, and methods to find the nth term and sum of the first n terms of an AP.


Key moments:
00:00 The video discusses arithmetic progression in Class 10th, explaining the concept of common difference and general form of an arithmetic sequence. It emphasizes adding common differences to each term to progress through the sequence.
-Introduction to arithmetic progression in Class 10th and the concept of common difference.
-Explaining the process of adding common differences to each term to advance through the sequence.
-Understanding the general form of an arithmetic sequence and the importance of recognizing common differences.
08:05 Understanding the concept of common difference in sequences is crucial for solving mathematical problems efficiently. By identifying patterns and applying simple arithmetic operations, such as subtraction, one can easily determine the common difference in a sequence.
-Explaining the concept of common difference in sequences and its significance in mathematics.
-Demonstrating how to calculate the common difference by subtracting consecutive terms in a sequence.
16:10 Understanding the common difference in a series of numbers is crucial in solving mathematical problems. Simplifying complex equations by identifying patterns and common differences can lead to accurate solutions.
-Importance of identifying common differences in mathematical series for problem-solving efficiency.
-Simplifying equations by recognizing patterns and common differences to reach correct solutions.
-Exploring the concept of air pressure in cylinders and the removal of air to understand the mathematical implications.
24:15 The video discusses solving mathematical problems involving fractions and percentages step by step, demonstrating the process of simplifying equations and understanding compound interest formulas.
-Solving mathematical equations involving fractions and percentages step by step.
-Demonstrating the process of simplifying equations and understanding compound interest formulas.
-Explaining the concept of common differences and common ratios in mathematical sequences.
32:19 Understanding arithmetic progressions is crucial in mathematics. The formula for finding the nth term in an arithmetic progression is essential for calculations and problem-solving.
-Arithmetic progressions are sequences with a common difference between consecutive terms, aiding in calculations and problem-solving in mathematics.
-The formula for the nth term in an arithmetic progression involves identifying the common difference and applying it to find specific terms in the sequence.
-Practicing arithmetic progressions and nth term formulas helps in developing problem-solving skills and understanding mathematical concepts effectively.
40:23 Understanding arithmetic progression formulas and identifying terms in a sequence is crucial for solving math problems efficiently. The video discusses how to determine the number of terms in a sequence using the arithmetic progression formula.
-Importance of mastering arithmetic progression formulas and recognizing terms in a sequence for efficient problem-solving.
-Exploring the concept of arithmetic progression and its application in determining the number of terms in a sequence.
-Demonstrating the process of verifying the arithmetic progression formula and calculating the number of terms in a given sequence.
48:28 Understanding the concept of common difference is crucial in solving equations with multiple variables. Checking the common difference helps determine the value of variables in the sequence.
-Importance of common difference in solving equations with multiple variables.
-Utilizing the common difference to find the values of variables in the sequence.
-Verifying the list of numbers and using the common difference concept to determine variable values.
56:30 Understanding the concept of finding the number of terms in a sequence divisible by 3 involves manipulating equations to determine the value of 'n' and the total number of terms in the sequence.
-Manipulating equations to find the value of 'n' and the total number of terms in the sequence divisible by 3.
-Explaining the concept of common difference and finding the common difference in the sequence.
1:04:36 Understanding arithmetic progressions involves finding the sum of terms using formulas. The video explains how to calculate the sum of terms in an arithmetic progression step by step.
-Solving arithmetic progression problems by calculating the sum of terms using specific formulas.
-Explaining the process of finding the sum of terms in arithmetic progressions with examples.
-Demonstrating the application of formulas to calculate the sum of terms in arithmetic progressions.
1:12:42 Understanding mathematical formulas and calculations can be simplified by breaking them down into smaller steps, making it easier to solve complex equations like n / 2 * 2a + n - 1 * d. It is important to approach calculations methodically and with confidence to achieve accurate results.
-Importance of breaking down complex equations. Simplifying calculations by focusing on individual components can lead to accurate results in mathematical problems.
-Methodical approach to calculations. Following a systematic method and having confidence in solving equations step by step can enhance accuracy and understanding of mathematical concepts.
-Significance of practicing calculations. Practicing mathematical calculations, even in a structured manner like children, can improve problem-solving skills and boost confidence in handling complex equations.
1:20:46 Understanding mathematical equations involving terms and values is crucial for solving problems efficiently. The video discusses solving equations step by step to find the values of variables in a given context.
-Importance of understanding mathematical equations and values for problem-solving efficiency.
-Step-by-step process of solving equations to determine variable values in a specific scenario.
-Application of mathematical formulas and calculations to find solutions in a structured manner.
1:28:49 The video discusses the mathematical calculations involved in determining the total production of TVs over seven years using a specific formula and solving for the length of a spiral made up of concentric circles.
-Calculation of total TV production over seven years using a specific formula and understanding the mathematical process involved.
-Solving for the length of a spiral made up of concentric circles by considering the radii and parameters of the circles.
-Deriving the total length of a spiral made up of concentric circles by calculating the parameters and common differences in the sequence.
1:36:54 The video explains a math problem-solving process step by step in Hindi, focusing on calculating the perimeter of a shape using given measurements and formulas.
-The importance of understanding mathematical concepts and applying formulas accurately for problem-solving.
-Encouragement to practice solving math problems independently to enhance understanding and retention of concepts.

[darshsharma]

I hope all students get 95 % in 10th board exam

[EXPECTANT_JEE_]

Math mein Lana hai 100/100=1mark best of luck everyone 🤣🤣
Who noticed it😁

[azizurvlogs]

I would like you to please make lectures for the following topics as your videos are much better as compared to other channels.
1) Chapter:3:Pair of Linear Equations in Two Variables
2) Chapter:4:Quadratic Equations
3) Chapter:6:Triangles
4) Chapter:10:Circles
5) Chapter:12:Areas Related to Circles
6) Chapter:13:Surface Areas and Volumes
7) Chapter:14:Statistics
I would really be grateful if you could cover these topics in your upcoming videos as these are my weak points.

[Harshiitokass]

Vote Now for The sequence Series: 1. Triangles
2. Areas related to circles
3. Circles
4. Statistics

[Binod-svjx]

1:23:00
Question. How many terms of the AP: 24, 21, 18 - - - - must be taken so that their sum is 78 ?
Solution
Let we take 'n' terms to make Sn = 78
n/2[ 2a+( n- 1 )d] = 78
a2 - a1 = 21 - 24 = -3
a3 - a2 = 18 - 21 = -3
Common difference (c.d) is same (-3)
n/2 [2(24)+ (n-1)(-3)] = 78
n/2 [ 48+(n - 1)(-3) = 78
78 = n/2 [48-3(n-1)]
78 = n/2(51-3n)
156 = 51n-3n^2
156-51n+3n^2 = 0
3n^2-51n+156 = 0
By using quadratic formula / Sridharacharya formula
a = 3, b = -51, c = 156
D = b^2 - 4ac
D = (-51)² - 4(3)(156)
D = 2601 - 1872 = 729
x = -b +- √D/2a
x = 51 +- √729/6
x = 51 + 27/6, x = 51 - 27/6
x = 78/6 = 13, x = 24/6 = 4
x = 13, 4
So, n can be either 4 or 13. Therefore, we must take either 4 or 13 terms of the AP for their sum to be 78.

[manjunathdinni]

Kis kis ke half yearly exam mai ye chapter aa raha hai vo like kare, usse ache marks milenge 😊😄

[jeyanthibalaji]

Thank you for the video..
Please do lectures on
1.Surface areas and volume
2.Triangles
3.statistics
4.Coordinate geometry
🙏 🙏

[Saktlonda]

This man is putting all the efforts to make our concept clear thank you Shobhit Bhaiya

[vidhiera]

1:23:10 Formula,

S
n
=
n
2
[
2
a
+
(
n
−
1
)
d
]

Given,

a
=
24
,
d
=
21
−
24
=
−
3
,
S
n
=
78

78
=
n
2
[
2
(
24
)
+
(
n
−
1
)
(
−
3
)
]

156
=
n
[
48
−
3
n
+
3
]

3
n
2
−
51
n
+
156
=
0

n
2
−
17
n
+
52
=
0

(
n
−
13
)
(
n
−
4
)
=
0

∴
n
=
4
,
13
Was this answ

[GS_MS]

1:23:20 there are 2 values of n. n=4 or n=13 For complete solution search this question on Youtube

[Thakur_ji]

Thank you bhaiya ❤
Guys Vote for CIRCLE ⭕
👇

[NTLEGEND]

Kon kon Final Exams ke liye dekh raha hai Like karo pass ho jaoge ache number leke 😂😂😂

[PooNam_chatkara]

1:10:02 / correction
11th annual salary received by Suba Rao will be ₹7000/-
It means after 10 years he'll get that money.
If 1995 is 1st year than 11th year will be 2005

[rfzkmpy]

Vote for these chapters
1-circle
2- Area realeated to circle
3- Triangles
4-Height & distance
Pls bhaiya upload these chapters as soon as possible 🙏🙏🙏🙏

[radha]

most funny time 😂1:06:59 .... well answer is a= 3, d= 7

[hebahussain]

As a senior i would suggest u all, trust him blindly BECAUSE OF HIM I HAVE SCORED 90% in my board exams he is putting his each and every effort just for u all love you sm bhaiya 🥺❤

[HarshKumar-snje]

35:30 If the principal amount is ₹10, 000 and it's being increasing at the rate of 7% compond interest then the amount of money after 1 year would be ₹10, 700.