Mathematical Olympiad | Learn to find the value of (1/a + 1/b + 1/c)^2022 | Math Olympiad Training

Can you find the value of (1/a + 1/b + 1/c)^2022 in the given system of exponential equations?

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Mathematical Olympiad | Learn to find the value of (1/a + 1/b + 1/c)^2022 | Math Olympiad Training

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[sybermaths]

Thank you teacher for always helping to teach. I have been following the teacher's video for many years 💗💗💗🙏🙏🙏☺️🥺I am Cambodian

[anjalidwivedi]

This seemed difficult.Nice Solution.
Thank u sir.

[Rizwanalam]

Great Video, I couldnt understand in the beginning but your video was awesome.Thanks

[bigm]

Sneaky little problem. Thanks Professor!👍🥂

[xaviersoenen]

I can simplify by 2
169=13²; 961=31²; 403=31x13
then 13^2a= (13x31)^(-2b)=31^2c
13^a=(13x31)^(-b)=31^c

[rangaswamyks]

You are genius sir
I worship you
You are my master

[mukundathavale]

Sir, l am 63 year old and solve problem immediately on publishing just to keep my brain active. I will like to know this problems are for which class students ?

[verganchun]

saludos, teacher para mi el error esta en que esta afirmando que el producto de 2 potencias positivas sea negativo, debia aplicar el triple producto entre ellas

[sonnyclief]

I already knew the answer is 0 when i saw the problem. Because 169^a = 961^c can be solved if a=c=0.

[verganchun]

Saludos desde Venezuela, teacher the answer is (1) no (0)

[giuseppemalaguti]

0, svolgendo i calcoli 1/a+1/b+1/c=0, percio anche la potenza 2022 dà 0

[verganchun]

Disculpe, Teacher error mio vi mal, mis disculpas

[mehulpunia]

I got confused in but you explained it very nicely

[randomjudgements]

Brilliant work sir
YOU ARE THE BEST 😊😊
KEEP UP THE WORK SIR
THIS QUESTION WAS AWESOME😇

[HappyFamilyOnline]

Awesome solution👍👍
Thanks for this amazing video🎉🎉

[massimiliano__]

saying that d^1/a = d^-1/b = d^1/c is not the same as saying that (d^1/a)*(d^1/c) = d^-1/b

[zplusacademy]

Extremely beautiful calculation ❤️🙏🙏🙏🙏sir really awesome ❤️🙏🙏🙏

[allesunsolar]

hi, can you share your solution for this ? | |…| |x -10| - 9| -...- 2 | -1 |=0