Solving an Exponential Equation

#Shorts #ChallengingMathProblems #ExponentialEquations via @YouTube @Apple @Desmos @NotabilityApp @googledocs @canva

[tbg-brawlstars]

Simple! I was thinking of using Lambert W function somehow...
Btw can you have some videos with Lambert W function?

[oenrn]

2^x = 3 means x = log_2 (3).
That's literally the definition of a log, no need to do all those manipulations at the end.

[bruhnish]

log(2^x^2)=log(3^x). (x^2)log2=xlog3. Divide by x. xlog2=log3. x=log3/log2=log_2(3)

[sarjarnesto]

bro you can't make 2^x^2 be equal to 2^x^x, that only works if x=2

[Shaam_Ark]

But one doubt if you continue the log(3)/log(2)

By condition won't it be log(3-2) which is log(1)

log(1) is zero so the answer will still remain 0?

[kitadriantiulamela]

He can’t explain well unlike the other channels that’s easy to understand because of how they elaborately explain stuff even in shorts.

[krama]

Bro ln 3/ln2=ln(3-2)=ln(1)=0 so zero is only solution I think can you check it

[packofskittles]

Can’t we just directly state that x=0??