Finding the horizontal and vertical asymptotes of a function

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👉 Learn how to find the vertical/horizontal asymptotes of a function. An asymptote is a line that the graph of a function approaches but never touches. The vertical asymptote is a vertical line that the graph of a function approaches but never touches. To find the vertical asymptote(s) of a rational function, we set the denominator equal to 0 and solve for x.

The horizontal asymptote is a horizontal line which the graph of the function approaches but never crosses (though they sometimes cross them). A rational function has a horizontal asymptote of y = 0 when the degree of the numerator is less than the degree of the denominator. A rational function has a horizontal asymptote of y = c, (where c is the quotient of the leading coefficient of the numerator and that of the denominator) when the degree of the numerator is equal to the degree of the denominator. A rational function has no horizontal asymptote if the degree of the numerator is greater than the degree of the denominator.

Organized Videos:
✅ Find the Asymptotes of Rational Functions
✅ Find the Vertical and Horizontal Asymptotes of a Rational Function y=0
✅ Asymptotes of Rational Functions | Learn About
✅ Find the Asymptotes of a Rational Function with Trig
✅ Find the Asymptotes and Holes of a Rational Function
✅ Find the Slant Asymptotes of the Rational Function

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you compare the leading degree for both polynomials 4=4. When the leading degree in the numerator is equal to that of the denominator you divide the leading coefficients. In this problem you will have 12/3 = 4. So your horizontal asymptote is y =4

brianmclogan
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sometimes, when the degrees are even you need divide the leading coefficients of each polynomial. That value is your horizontal asymptote

brianmclogan
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awesome, let me know if there is anything else I can do for you

brianmclogan
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Just trying to help, a lot of other teachers have great videos.

brianmclogan
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what if both degrees are equal? does that make the Horizontal Asymptote = 1?

DawitTes
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Thank you for the help, now I understand.

DrSwagMeOut
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what if the horizontal asymptote is different, for example 12x^4+10x-3over3x^4, i dont know which degree im supposed to compare

drainurlife
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thanks for your help man! going to Ace this test

drainurlife
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finally a clear video of this topic not like this garbage
/watch?v=0-sKIdNqo5M

mikey
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you distributed wrong as it should’ve been x^3 - 2x^2

dshah