1(3) + 3(5) + 5(7) + … + (2n-1)(2n+1)

In this video, we will derive the closed form of series 1 times 3 + 3 times 5 + 5 times 7 + so on up to n terms.

We will apply the closed from of sum of squares of first n natural numbers. Link of the video explaining the derivation of closed from of 1^2 + 2^2 + 3^2 + … + n^2 is given below:

Other topics of the video:
Evaluate 1(3) + 3(5) + 5(7) + … + (2n-1)(2n+1)
How to evaluate 1(3) + 3(5) + 5(7) + … + (2n-1)(2n+1)?
What is the closed form of 1(3) + 3(5) + 5(7) + … + (2n-1)(2n+1)?
How to find the value of 1(3) + 3(5) + 5(7) + … + (2n-1)(2n+1)?
How to find closed form of 1(3) + 3(5) + 5(7) + … + (2n-1)(2n+1)?
Evaluate 1.3 + 3.5 + 5.7 + … + (2n-1)(2n+1)
How to evaluate 1.3 + 3.5 + 5.7 + … + (2n-1)(2n+1)?
What is the closed form of 1.3 + 3.5 + 5.7 + … + (2n-1)(2n+1)?
How to find the value of 1.3 + 3.5 + 5.7 + … + (2n-1)(2n+1)?
How to find closed form of 1.3 + 3.5 + 5.7 + … + (2n-1)(2n+1)?