Sum of 3 odd numbers equal to 30 | Find numbers from 1,3,5,7,9,11,13,15 to make sum 30

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Mathematical Puzzle : () + () + () = 30 using 1,3,5,7,9,11,15.
Or

What is _ + _ + = 30 using 1,3,5,7,9,11,15.
Or
Can you find 3 odd numbers with sum 30.

Can you solve this riddle? Only a genius can solve it !
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Me- i found this video because someone forward me this question on WhatsApp 😂😂😂

kirtiratre
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There is no way to make possible to solve this equation by using 3 single odd number. It must be using any other rules like decimal, fraction or another math formula. And who use those then he brake the condition. So, this equation is foul or we are such stupid to trying to solve this problem. It is a nonsense math puzzle as like as nonsense rhyme.

ThisisMonzur
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It's a logical question, use total hours as a logic for this solution.
1(day)+3(Hrs)+3(Hrs) = 30 Hours

gopikishorelella
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15 + 15 + Null = 30. Nothing stated requires you to fill in ALL the boxes. Boxes as stated is plural so you have to fill in at least 2 boxes... the third box can be NULL (nothing filled in).

lgovantes
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I find this question really study. Logically speaking there is no way that could be done using the numbers provided. This needs to be worded properly.

Lovely-wvyq
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Ok so since theres no rules other than fit it into the box so we’re gonna use some exponents so theres 1, 3, 5, 7, 9, 11, 13, 15 and if we do say 3 to the power of two we get 9 so lets say 9 + 15 = 24 so close but lets say 3 to the power of 2 so that would be 27 and i you do 3 to the power of 3 plus 3 than you get 30 as 27 + 3 = 30 so the answer is 3 to the power of 3 plus three but theres another box to fill in so we scrape it and it didnt say anything about using it as time so if we do 1(day) = 24 (h) + 3(h) =27(h) + 3(h) we get 30(h)

Thetravelingmonke
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sucessor function: S(n)=n+1
so 15+13+S(1)=30

neverdie
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what's about this- (15) + (13) + (3-1)= 30

amitars
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Proof:- Sum of 3 odd numbers can never be equal to a even number.
Let's take 3 No.s = a1, a2, a3
a1=2p-1, where p=0, 1, 2, 3...
a2=2r-1, where r=0, 1, 2, 3....
a3=2z-1, where
Considering this are 3 boxes to be
So, (2p-1)+(2r-1)+(2z-1) !=30
=>2(p+r+z) - 3 != 30
=>2(p+r+z) != 33
So, 2(p+r+z) must be a Even no.Since, it is multiplied by 2.
Hence proved

richikchakraborty
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Rotate the 9 to a six now plus it with 11 and 13

teamdreamers
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Answer is 9.3+9.7 +11=30. This question didn't say that I couldn't use point. I used odd # and repeated it with 9, 3, and 7

welcometomychannelswelcome
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My proof that zero is more suitable for the third box is because zero is neither an even or odd number, odd numbers begins with one while even begins with 2

iyoboimongan
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पर उसमे 6 तो है ही नहीं फिर 6 कैसे आपने add कर लीया ये बताए सर

prafulpandane
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sir instead of rotating techniques we can place both odd numbers to make even numbers like
(3-1) +15+13=30,
9+11+(15-5)=30,
7+(13-5)+15=30,
so by that, we can keep the bracket number in one box and it will be easy to understand.

PavanKalyan-upnu
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The question is can you solve this?
The ans is No😁

Am-xtvl
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Use the brackets and tilt the + to make: (3×5)+15=30

michelekalu
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Rotate the nine into six and then 11+13+ your new number the six equals 30

kayleemorrison
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Hahha... The question is correct but the way of presenting the question is wrong. How can we use additional numbers or forms like .5 or ! while it's stated that brackets with numbers clearly,

MyCollectionz
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The answer is 13, 11, and 6. You can get 6 by flipping the 9 or by using arithmetic, I think.

toricorn
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Hi
These methods cant work beacuse you are using things that is not thier
For example
Where did you get the dismals from

I say the answer to the puzzle is

(No)

As they ask you

Can you solve this?

Best wishes

Ali
IRAQ

TD-pwtq