Naming Alkenes and Alkynes on the same Compound - ENYNE *Error at 3:18*

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This video is Part 8 in the Naming Organic Compounds series

This nomenclature tutorial video takes you through the IUPAC rules for naming molecules containing both a double and triple bond on the same compound. This is demonstrated using my puzzle piece approach to IUPAC naming with simple and substituted examples

Many students struggle with naming because they attempt to come up with the entire name at once and often wind up missing a piece or two. After this series you won't have that problem anymore

Visit my website for additional naming tutorials:

And of course my ebook: "10 Secrets To Acing Organic Chemistry"

For questions and comments, find me on social media here:
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You should remove and reupload this video. It's one of the top google hits for naming alkenes and alkynes and even the thumbnail shows an incorrect name. My students showed me this and asked for credit on an assignment. The compound at 4:00 should be 7-methyloct-3-en-5-yne. Substituents do not influence the numbering direction when there are unequal functional groups equidistant from both ends - they should be numbered based on the functional group priority. Also the double bond should be -en- when another functional group is after it in the name.

aa
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Hi...
Thank you so much for clearing my doubts
I have a question ...
Which is right :
1) 1-butene -3- yne
Or
2) but-1 ene -3- yne

StudyTime-dkys
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I agree with 06moca1 the carbon chain should not be prioritized based off of the methyl substituent. The double bond should have the lowest possible numbering

lmeflash
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Videos are amazing, indeed you are heaven sent. Thanks a
Please do you have videos on Resonance, Lewis acids and bases. Topics that have to do with conjugate acids and conjugate base?

elizabethadegbite
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w0w ! thank you very much for the videos. my midterm exam is in monday and im really confused with this topic. thanks for uploading your video !

leeyani
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my professor says that double or triple bonds will get priority over substituents @Leah4sci could you please address this? It seems that there is a great deal of confusion regarding this

SharonGHSwag
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Enjoyed your video. Small point : remember that ene followed by yne you drop the last e in ene!

clydec
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I appreciate that you pointed out the error at 3:18, but why not specify what the error was, in the title or in the description or a pinned comment?

PunmasterSTP
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Question: if there is both yne, ene and oic acid in the compound, then we know oic acid should come the last as the main functional group. Though alphabetic order will put ene, oic acid and then yne. Why in this video, we are putting yne after ene though ene is the high priority functional group? Thanks in advance.

ShamirMontazid
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please what is the correct name for the compound at 4:00 cos it is confusing me.

olugbengaakinrimisi
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is the correct name for the last compound in the video is 7-methyloct-3-en-5-yne?

FalconX
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how come in an example with a cyclic alkene, the pi bond gains priority over a substituent, but in an alkane chain the substituent gains priority over the alkene?

luckygrl
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isnt double bond need to be on the lowest number?

marrilynz
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thank you 🥺🥺🥺 you explained it so well!!❤

dameriasimbolon
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Thankyou so much!I understood it really well..Need to clarify one more thing....even in the presence of multiple bonds substituents should get the lowest number(eg:OH, ethyl, methyl, etc.)correct?+Leah fisch

nethmawethalawe
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thank you sister i appreciate your teaching method

kevinhunda
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Wow!You are making it easier.I would like to have more tutorial with you😊😌

samuelndirangu
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aren't you suppose to drop the last e "ene" because its in the middle

papichulocod
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Thank you! But I have a question, why is it in the last sample you prioritize triple bond (-yne) even though they have the same position of double bond (-ene)?

lesliegutierrez
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hi i have a question should i drop 'e' in (ene) like (hex-1-en-4-yne) right?

yans