Solving Higher Order Linear Differential Equations - Ordinary Differential Equations | Lecture 20

In this lecture we demonstrate how to solve arbitrary order linear ODEs with constant coefficients. Like their second order counterparts, we arrive at a characteristic equation for which we must identify its roots to find the solutions. In this case the characteristic equation is a polynomial of degree equal to the order of the differential equation, and therefore finding its roots is a nontrivial task. This video lecture is comprised of illustrative examples that demonstrate how to solve the characteristic equation, especially in the case when the roots are complex.

This course is taught by Jason Bramburger for Concordia University.

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[kingplunger]

When finding the roots of the example the intermediate equation has a -6 and not a -1 at the end, otherwise -1, 2, -3 wouldn't be roots