29. Advance Illustration | Fluid Statics & Dynamics | Vertically floating Glass Tube | Ashish Arora

The website, aimed at nurturing grasping power students, has classroom lectures on almost all the topics. It is an outcome of 23-year long toil of Physics expert who has made it a mission to simplify the complexities of Physics.

Ashish Arora, the brain behind this interactive unique website, has all his lectures available on web for free of cost. He has created a youtube channel in the name of Physics Galaxy. Today more than 6000 video lectures are being watched per day on this website which is highest among any other e-learning website in India. Till now more than 3.6 Million videos are watched on it. On each video subtitles are also available in 67 languages using google translator including English, Hindi, Chinese, French, Marathi, Bangla, Urdu and other regional and international languages.

Besides uploading transcripts of all his videos, he has created a software based synchronized European voice accent of all videos to benefit students in USA, Europe and other countries.

#AshishArora #JEEAdvanced #JEE2020

[TargetIITBatch]

For those who didt understood ...
the center of boyancy is like the com of liqud displaced here the shape of the liquid which got displaced also matter to determine cob... all the boyant force can be asumed to be at that point so when this point is above the com of the body the torq by boyant force always try to ensure that liq is upwards..
but when this point is below com this always appoy torq to topple the object ....

[_Anmol-ohiu]

THANK YOU VERY MUCH SIR FOR GIVING THESE TOP NOTCH EDUCATION ACESSIBLE TO ALL AT FREE OF COST..

[jainamshah]

People looking for explanation of torque is that when you displace tube by small angel, the torque of boyancy should be less than that of mg, so if com is above the point of boyancy, torque of boyancy will be more and it will rotate it. As Fb= mg. In other two cases point of botancy equals to com and less than com net torque is 0 and clockwise respectively and tube will be stable

[kMEAmartyaPrabhakar]

Respected sir Thanks a lot for uploading this question.
After watching this i really felt i learnt a new and an amazing thing.
Thanks again sir.

[subratabhattasaly]

i think x = (30 + Ayp)/Ap. isn't it?

[keshavbaldeva]

Here both gravitational and Buyouncy force are in verticle direction then how torque acting on tube.
Please help me to understand this. 🙏🏻

[maneeshsethi]

Sir which torque are you talking about? There is no torque about the axis of cylinder whatever be the position of center of gravity and center of buoyancy

[satyajeetrai]

Sir value of x = 30/rho +Ay/A u missed rho but how you calculate answer or is there anything I am missing plz help me

[vijayvyas]

Sir, if I have all the advanced illustrations on my tips, and the concepts clear, then can I clear jee advanced with all India under 1000 rank? Provided maths and chemistry are good.