27. Advance Illustration | Fluid Statics & Dynamics | Fluid ejecting out from a Rotating Tube

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Can be done by direct formula derived in theory:

∆P=pw²(l²-((l-h)²)/2


We can't just directly apply at rotating axis and hole directly as fact in between liquid isn't present thus rho=0, hence result won't uniform

Using Bernoulli will get same answer, basically both method are similar if you remember rotating tube horizontal result with proper notation and understanding

Remember: in formula

*P=rho.w².x²/2 (x→ Distance of point from rotating axis)*

anmolempire
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Can be handeled without integration with help of com method
Centripetal acceleration =(l-h/2) w^2
P at b - P atm = rho. (L-h/2) w^2 .h

learnwithme
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Sir, problem 1.326 is similar to that u have taken in the basic theory video ?

adarshchaturvedi
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It's a question similar to that given in irodov

RohitKumar-gzki
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Sir, How can we apply bernoulli's equation the way you mentioned at0.52 as we derived bernoulli's equation only in the case pressure forces are doing work, but here centrifugal force also do work. How can we apply that?

amanaloon
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As tube is also rotating... Won't the fluid coming out be having two velocities.. One due to efflux.... And another due to rotation. .. So we have to calculate resultant of both.

integration_IIT_ISM
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Why applying Bernoulli theorem just inside and outside points.?

aayushsingh
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Sir if we apply bernoulli at open end of tube on left side and just outside the orifice then bernoulli eqn will be: P(atm)=1/2ρv^2 + P(atm). But ans js coming wrong. Please help

vatsalgoyal
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Confused as I am not getting correct ans by applying Bernoulli at open end and point B...

satvik_srivastav
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We can apply ber theorm at any two points . If I take limits from l-h to a (a general point) then the answer would be different . How so !

dsgfhgjkjhnbmnhkglgj
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Why don't we apply Bernoulli at other point like from where the liquid starts?if we can then how?

KaranDoshicool
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Sir at point x can velocity be (Omega*l) why it is taken as zero plz reply sir it is very confusing

sd
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sir if we consider pressure below a datum level to be pgh then won't potential energy become -pgh and won't they cancel out

swethasrinivasan